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Olenka [21]
2 years ago
6

Jen and her partner were assigned the Zn/Zn cathode/anode pair which they used to construct their electrolytic cell. They decide

d to keep the concentration of the corresponding Zn2+ solution constant at 1 M. If Jen ran her cell for 22.8 mins, what current (mA) did she use in order to transfer 9 x 10^-4 moles of electrons?
Chemistry
1 answer:
Darya [45]2 years ago
5 0

Answer:

63.2 mA

Explanation:

We all know that:

CurrentI = \dfrac{Q}{t}

which can be further expressed as:

I = \dfrac{ne}{t}

where;

n = number of electrons

e = charge on electrons

t = time (second)

Then; by replacing the values in the question, we have:

\dfrac{(9*10^{-4})\times6\times10^{23}\times1.6\times10^{-19}}{22.8\times60}

= 0.06316 A \\ \\ \mathbf{I= 63.2 \ mA}

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Answer:

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Explanation:

Start with the balanced equation:

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This tells us that 3 moles of CuCI2 react with 2 moles Na3PO4-

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We know that concentration = moles/volume i.e:

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Explanation:

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