Question

Jen and her partner were assigned the Zn/Zn cathode/anode pair which they used to construct their electrolytic cell. They decided to keep the concentration of the corresponding Zn2+ solution constant at 1 M. If Jen ran her cell for 22.8 mins, what current (mA) did she use in order to transfer 9 x 10^-4 moles of electrons?

Answer 1

Answer:

63.2 mA

Explanation:

We all know that:

Current$I = \dfrac{Q}{t}$

which can be further expressed as:

$I = \dfrac{ne}{t}$

where;

n = number of electrons

e = charge on electrons

t = time (second)

Then; by replacing the values in the question, we have:

$\dfrac{(9*10^{-4})\times6\times10^{23}\times1.6\times10^{-19}}{22.8\times60}$

$= 0.06316 A \\ \\ \mathbf{I= 63.2 \ mA}$