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3 years ago

The length of a rectangle is 5t+6 and its height is t^6 , where t is time in seconds and the dimensions are in inches. Find the

rate of change of area, A, with respect to time

Mathematics

1 answer:

Nataly_w [17]3 years ago

7 0

$\bf \textit{area of a rectangle}\\\\
A=l\cdot w\qquad 
\begin{cases}
l=length\\
w=width\\
-----\\
l=5t+6\\
w=t^6
\end{cases}\implies A(t)=(5t+6)t^6
\\\\\\
A(t)=5t^7+6t^6\implies \cfrac{dA}{dt}=35t^6+36t^5$

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A shoe company found that 4.25% of the production is defective. The company

nlexa [21]

1190 pairs of shoes are defective

Solution:

Given that shoe company found that 4.25% of the production is defective

The company made 28,000 pairs of shoes

To find: Number of pairs of defective shoes

From given information, 4.25% of the production is defective which means 4.25% of 28,000 pairs of shoes

Defective shoes = 4.25% of 28,000

Defective shoes $= \frac{4.25}{100} \times 28000$

Defective shoes $= 4.25 \times 280 = 1190$

Thus 1190 pairs of shoes were defective

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3 years ago

Hi there! Sorry to bother you, but can someone help me out with this?

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3 years ago

I can’t find this answer, help me plss

Vinvika [58]

2) 7/4×(22–x) =0

soln

= 7/4×(22 –x) =0

= 1.75 ×22 –x =0

= x=38.5

9) 15x² /7 =8x²/5

soln

= 15x²×8x²=7×5

=120x^4 = 35

= x^4 =120–35

x^4 =85

6) 9x²/4–4=0

soln

=9x²/4–4=0

=2.25–4=0

=4–2.25=0

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<h2>sorry I know that much </h2>

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3 years ago

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barxatty [35]

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2 years ago

Translate each of these statements into logical expressions by using quatifiers and predicates with one or two variables. (a) A

nikdorinn [45]

Answer:

a) $A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$ , b) $B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$ , c) $C = \{\forall x \in M\,|\,xI \}$ , d) $D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$ , e) $E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

Step-by-step explanation:

a) x - A student, M - Set of students of discrete math class, G - has lived in, y - Florida, U - Set of states of the United States of America.

$A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$

b) x - A student, M - Set of students of discrete math class, y - A perfect grade, H - Midterm I.

$B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$

c) x - A student, M - Set of students of discrete math class, I - loves discrete math.

$C = \{\forall x \in M\,|\,xI \}$

d) x - A student, M - Set of students of discrete math class, J - has been in, y - a state, U - Set of states of the United States of America.

$D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$

e) x - A student, M - Set of students of discrete math class, J - has been in, y - a city, V - At least one state of the United States of America, U - Set of states of the United States of America.

$E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

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3 years ago