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elixir [45]
3 years ago
8

The length of a rectangle is 5t+6 and its height is t^6 , where t is time in seconds and the dimensions are in inches. Find the

rate of change of area, A, with respect to time
Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0
\bf \textit{area of a rectangle}\\\\
A=l\cdot w\qquad 
\begin{cases}
l=length\\
w=width\\
-----\\
l=5t+6\\
w=t^6
\end{cases}\implies A(t)=(5t+6)t^6
\\\\\\
A(t)=5t^7+6t^6\implies \cfrac{dA}{dt}=35t^6+36t^5
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Someone answer this please
navik [9.2K]

Answer:

b = 33m is the answer

Step-by-step explanation:

a = 44m

b = ?

c = 55m

According to the Pythagoras theorem,

a² + b² = c²

44² + b² = 55²

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b² = 3025 - 1936

b² = 1089

b = 33m

∴ b = 33m is the length of the missing leg.

3 0
2 years ago
Warren drives half the distance Kendall drives to work. Kendall drives 26 more miles to work than Joe. Warren drives 15 miles. W
dem82 [27]

Answer:

15 times 2 - 26 = x

Step-by-step explanation:

Warren drives half the distance Kendall drives to work. Kendall drives 26 more miles to work than Joe. Warren drives 15 miles. Write an equation that models this situation. Use x to represent the number of miles Joe drives to work.

W X 1/2 = K

K - 26 = J

so 15 times 2 - 26 = x

6 0
2 years ago
Read 2 more answers
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