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sergey [27]
3 years ago
5

What is the LCM (12, 15)?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

60

Step-by-step explanation:

12x5=60 and 15x4=60 so 60 is the LCM

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Y + 3=2/3(x + 6) in standard form.
Soloha48 [4]

The standard form of this equation is y = 2/3x + 1

To find this, you first need to distribute the 2/3 in front of the parenthesis.

y + 3 = 2/3(x + 6)

y + 3 = 2/3x + 4

Now you can subtract 3 from both sides to isolate the y.

y = 2/3x + 1

8 0
3 years ago
18. Given the following four lines, pick the true statement.
Sav [38]

Answer:

Lines 2 and 4 are perpendicular

Step-by-step explanation:

Line 2: 4y=3x-4

y=3/4x - 1

Line 4: 4x+3y=-6

3y=-6-4x

y=-2 - 4/3x

The two lines are perpendicular since -4/3= - (inverse of 3/4)

8 0
3 years ago
Read 2 more answers
write the equation of the line that passes throughout (-1,5) and has a slope of 3 in point-slope form
SpyIntel [72]
The point-slope form is:
y - k = m(x-h)

So, here, you just plug in values:
y - 5 = 3(x+1)

It would be + 1 because remember, the '-' sign just means the opposite of, not subtraction in this case. Also, m = slope.
4 0
4 years ago
Six times a number is greater than 20 more than that number. What are the possible values of that number?
Fynjy0 [20]

Answer:

n > 4 is the possible value of number

Step-by-step explanation:

Let number = n

Given that:

Six times a number is greater than 20 more than that number

It will make the equation like:

6n > 20 + n

Subtracting n from both sides

6n - n > 20 + n - n

5n > 20

Dividing both sides by 5 we get:

5n / 5 > 20/ 5

n > 4

I hope it will help you!

3 0
3 years ago
Which points are the approximate locations of the foci of the ellipse? Round to the nearest tenth. (−2.2, 4) and (8.2, 4) (−0.8,
Studentka2010 [4]

The graph is attached.

Answer:

(-2.2, 4) and (8.2, 4)

Step-by-step explanation:

In an ellipse, there is a minor radius and a major radius.

Let major radius be = a

Let minor radius be= b

From the graph, we are given:

Major radius, a = 6

Minor radius, b = 3

Now, let's find the distance from the center to the focus using the formula:

\sqrt{a^2 - b^2}

Substituting values, we have:

= \sqrt{6^2 - 3^2}

= \sqrt{36 - 9}

= \sqrt{27} = 5.916

≈ 5.2

We can see from the graph that center coordinate is (3, 4). Therefore, the approximate locations of the foci of the ellipse would be:

(3-5.2, 4) and (3+5.2, 4)

= (-2.2, 4) and (8.2, 4)

3 0
3 years ago
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