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gtnhenbr [62]
3 years ago
9

Marking brainliest Please help

Mathematics
2 answers:
GuDViN [60]3 years ago
6 0

Answer:

noisy I think because of how they're describing them

pychu [463]3 years ago
6 0

Step-by-step explanation:

Pistol Shrimp are noisy.

You might be interested in
Absolute value of -392
Tema [17]

Answer:392

i need help plz help and here is a explanation i hope this helped

step-by-step :

Formally, the absolute value of a number is the distance between the number and the origin. This is a much more powerful definition than the "makes a negative number positive" idea. It connects the notion of absolute value to the absolute value of a complex number and the magnitude of a vector.

The absolute value of x, denoted "| x |" (and which is read as "the absolute value of x"), is the distance of x from zero. This is why absolute value is never negative; absolute value only asks "how far?", not "in which direction?" This means not only that | 3 | = 3, because 3 is three units to the right of zero, but also that | –3 | = 3, because –3 is three units to the left of zero. You can see this on the following number line:

abs(-3) = abs(3) = 3

Warning: The absolute-value notation is bars, not parentheses or brackets. Use the proper notation; the other notations do not mean the same thing.

It is important to note that the absolute value bars do NOT work in the same way as do parentheses. Whereas –(–3) = +3, this is NOT how it works for absolute value:

Simplify –| –3 |.

Given –| –3 |, I first need to handle the absolute-value part, taking the positive of the insides (the "argument of" the absolute value) and then converting the absolute value bars to parentheses:

–| –3 | = –(+3)

Now I can take the negative through the parentheses:

–| –3 | = –(3) = –3

As this illustrates, if you take the negative of an absolute value (that is, if you have a "minus" sign in front of the absolute-value bars), you will get a negative number for your answer.

Side note: When typing math as text, such as in an e-mail, the "pipe" character is usually used to indicate absolute values. The "pipe" is probably a shift-key somewhere north of the "Enter" key on your keyboard. While the "pipe" denoted on the physical keyboard key may look like a "broken" line, the typed character should display on your screen as a solid vertical bar. If you cannot locate a "pipe" character, you can use the "abs()" notation instead, so that "the absolute value of negative 3" would be typed as "abs(–3)".

Here are some more example simplifications:

Simplify | –8 |.

| –8 | = 8

Simplify | 0 – 6 |.

| 0 – 6 | = | –6 | = 6

Simplify | 5 – 2 |.

| 5 – 2 | = | 3 | = 3

Simplify | 2 – 5 |.

| 2 – 5 | = | –3 | = 3

Simplify | 0(–4) |.

| 0(–4) | = | 0 | = 0

Why is the absolute value of zero equal to "0"? Ask yourself: How far is zero from 0? Zero units, right? So | 0 | = 0.

Simplify | 2 + 3(–4) |.

| 2 + 3(–4) | = | 2 – 12 | = | –10 | = 10

Simplify –| –4 |.

–| –4| = –(4) = –4

In the next three examples, pay particular attention to the difference that the location of the square makes, with respect to the "minus" signs.

Simplify –| (–2)2 |.

–| (–2)2 | = –| 4 | = –4

Simplify –| –2 |2

–| –2 |2 = –(2)2 = –(4) = –4

Simplify (–| –2 |)2.

(–| –2 |)2 = (–(2))2 = (–2)2 = 4

5 0
3 years ago
PLEASE ANSWER!!! I WILL GIVR U BRAINLIEST!!
Tpy6a [65]

Answer:

k = 5

Step-by-step explanation:

The standard form of an equation representing proportionality is

y = kx ← k is the constant of proportionality

y = 5x ← is in standard form

with k = 5

6 0
3 years ago
Read 2 more answers
2. (08.05 HC)
4vir4ik [10]

Answer:

option 3

Step-by-step explanation:

not sure if right

8 0
2 years ago
S=2WH+2WL+2HL SOLVE FOR L
RSB [31]
2WH+2WL+2HL=S\\\\2WL+2HL=S-2WH\\\\L(2W+2H)=S-2WH\\\\\boxed{L=\frac{S-2WH}{2W+2H}}
6 0
3 years ago
The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili
Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

X = 71

Z = \frac{X - \mu}{s}

Z = \frac{71 - 74}{1.2274}

Z = -2.45

Z = -2.45 has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0
3 years ago
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