The correct equations of a parabola are z = 2(y-9)²-2 and y = 2(z-2)²-9.
This is a problem with coordinate geometry. We can solve this by following a few steps.
First of all we should know the ideal equation of a parabola. The equation is,
- where ( h, k ) is the vertex of the parabola.
From all those options only last two equations satisfy the conditions.
Where the coordinate of the vertex of this parabola is ( 9, 2 ).
Hence we can conclude that z = 2(y-9)²-2 and y = 2(z-2)²-9 are the correct equation of a parabola.
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Answer:
8 × 10¹
Step-by-step explanation:
don't panic. just breathe deeply and then think logically.
0.002 ... what is that ? 2 10ths ? 2 hundredths ? 2 thousandths ? 2 tenthousandths ?
the 3rd position after the decimal point is for 1/1000.
and that means 10^-3. in the same way as 1000 is 10³.
so, it is 2 × 10^-3.
the other rounded number is then 4 × 10⁴.
now, we are multiplying both numbers
2×10^-3 × 4×10⁴
what do we do ?
we combine the same types of factors, like the basic constants : 2×4 = 8
and 10^-3 × 10⁴.
what hairball when we multiply the same base number with exponents ? we add the exponents :
10^-3 × 10⁴ = 10¹ = 10
because -3 + 4 = 1
and so, the result is
8 × 10¹
Answer:
See below. The series converges.
Step-by-step explanation:
A). I would start at $100 through $200. since the range doesn't start until $110 there is no reason to show the numbers 0-90.
b). I would then go up by 10 on each interval. going up by 10 can easily be graphed and accurate.
The sum of the series 
is 44.
Step-by-step explanation:
The given series is 
To find the sum of the series, we need to substitute the values for k in the series.
![\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]](https://tex.z-dn.net/?f=%5Csum_%7Bk%3D1%7D%5E%7B4%7D%5Cleft%282%20k%5E%7B2%7D-4%5Cright%29%3D%5Cleft%5B2%281%29%5E%7B2%7D-4%5Cright%5D%2B%5Cleft%5B2%282%29%5E%7B2%7D-4%5Cright%5D%2B%5Cleft%5B2%283%29%5E%7B2%7D-4%5Cright%5D%2B%5Cleft%5B2%284%29%5E%7B2%7D-4%5Cright%5D)
Now, simplifying the square terms, we get,
![[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]](https://tex.z-dn.net/?f=%5B2%281%29-4%5D%2B%5B2%284%29-4%5D%2B%5B2%289%29-4%5D%2B%5B2%2816%29-4%5D)
Multiplying the terms,
![[2-4]+[8-4]+[18-4]+[32-4]](https://tex.z-dn.net/?f=%5B2-4%5D%2B%5B8-4%5D%2B%5B18-4%5D%2B%5B32-4%5D)
Subtracting the values within the bracket term, we get,
Now, adding all the terms, we get the sum of the series,
Thus, the sum of the series is
