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Lapatulllka [165]
3 years ago
9

Can you solve this integral?

0" id="TexFormula1" title=" \int\limits^a_b { x^{2} } \, dx " alt=" \int\limits^a_b { x^{2} } \, dx " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0
\frac{1}{3}(a^3-b^3)
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PLSSS<br><br> C= <img src="https://tex.z-dn.net/?f=%5Cfrac%7B12%5E%7B3%7D%20.%206%5E%7B5%7D%20%7D%7B9%5E%7B4%7D%20.%202%5E%7B10%
Rudiy27

Answer:

2

Step-by-step explanation:

The trick here is to reduce each of the bases to lowest form first

12 = 3.4 = 3 .2.2  = 3.2^{2}\\12^{3}  = (3.2^{2} )^{3} = 3^{3}2^{6}  \\6 = 3.2\\6^{5} = (3.2)^{5} = 3^{5} .2^{5} \\\\Numerator = 3^32^63^52^5 = 3^82^{11}\\Denominator computation\\9 = 3^2\\9^{4} = (3^{2} )^4 = 3^{8} \\Denominator = 3^82^{10} \\\\\frac{Numerator}{Denominator }  =\frac{{3^8}{2^{11} }}{3^82^{10}} = \frac{2^{11}} {2^{10}} = 2^1 = 2  

7 0
2 years ago
Which are the next four digits in the repeating decimal 4.715
skad [1K]
Answer. .7157
Explanation. If the decimal is repeating, we must continue the pattern. Hope this helps, let me know if it’s correct so others can use it :)
Good luck.
6 0
2 years ago
2x/x-3 - 6/x-3 . I need a step by step explanation , please
Harman [31]
When adding/subtracting fractions you need a common denominator, but you already have one, which is x-3.  So in general:

a/c-b/c=(a-b)/c so you just have:

(2x-6)/(x-3)  now if you factor 2 from the numerator

2(x-3)/(x-3)  the (x-3)s cancel out leaving

2

However!  Note that division by zero is undefined, so x cannot equal 3.  (because both original fractions had denominators of x-3)

What this all means is that that expression will equal 2 for all real values of x other than 3.
8 0
3 years ago
Find the slope of a line that goes through the two points (-1, 1) and (-3, -7).
il63 [147K]

Answer:

the slope of the line is <u>4</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>working</u><u> </u><u>is</u><u> </u>in the attached picture

3 0
2 years ago
Read 2 more answers
Frank, who lives in Texas, and his sister Lilly, who lives in Japan, correspond regularly. From what he can tell from the postma
Hoochie [10]

Question:

The available options are:

(A) There is convincing evidence that there is no difference in the mean delivery times.

(B) There is convincing evidence that there is a difference in the mean delivery times.

(C) There is convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(D) There is not convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan. (E) The t-test cannot be used for sample sizes that are this small.

Answer:

The correct option is;

(A) There is convincing evidence that there is no difference in the mean delivery times.

Step-by-step explanation:

Here we have the formula for the two-sample t-test given s;

t =\frac{\overbar\overline{\rm x}_1 - \overbar\overline{\rm x}_2 }{\sqrt{\frac{\sigma ^2_1}{n_1} } +\frac{\sigma ^2_2}{n_2} }}    

To Texas N₁ = 12,  \overline{\rm x}_1 =8.74 σ₁ = 2.92 SE Mean₁ = 0.84

To Japan N₂ = 9  \overline{\rm x}_2 = 6.75 σ₂ = 2.56 SE Mean₁ = 0.85

t =   1.667

Where the null hypothesis is

mu To Texas = mu To Japan and the alternative is

mu To Texas > mu To Japan

Here since the observed P value of P = 0.058 is greater than the significance level of 0.05 we fail to reject the null hypothesis and we will therefore, not accept the alternative hypothesis.

Hence, there is convincing evidence that there is no difference in the mean delivery times.  

3 0
3 years ago
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