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Lapatulllka [165]
3 years ago
9

Can you solve this integral?

0" id="TexFormula1" title=" \int\limits^a_b { x^{2} } \, dx " alt=" \int\limits^a_b { x^{2} } \, dx " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0
\frac{1}{3}(a^3-b^3)
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20/2.5 = 8
So 8 movies can be shown in 20 hours.
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One human year is said to be about 7 dog years. Cliff's dog is 5.5 years old in
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You need to rent a bowling lane. On Friday nights, you have two options. Option A is a $20 lane rental plus $3 per game. Option
ExtremeBDS [4]

For 5 games, the cost will be equal for each option.

Step-by-step explanation:

Given,

Lane rental of offer A = $20

Per game charges = $3

Let,

x be the number of games.

A(x) = 3x + 20

Lane rental is $35 for maximum 10 games.

B(x) = 35

For the cost to be same;

A(x) = B(x)

3x+20=35\\3x=35-20\\3x=15

Dividing both sides by 3

\frac{3x}{3}=\frac{15}{3}\\x=5

For 5 games, the cost will be equal for each option.

Keywords: function, division

Learn more about functions at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

6 0
2 years ago
How do I solve x-11/2<-7
Mekhanik [1.2K]

Answer:

x < -3

Step-by-step explanation:

1. multiply both sides by 2

2. isolate the x by adding 11 to both sides

3. simplify

(i have included an attachment showing the work for clarification)

4 0
2 years ago
The probability distribution of random variable, X, is defined as follows:
stealth61 [152]

Answer and Step-by-step explanation:

A) For the model to be a probability distribution, it has to follow two conditions:

1) The probability of each value of the discrete random variable is between, and included, 0 and 1:

2) The sum of all probabilities is 1;

In the table shown, the probabilities are from 0 to 0.3 - between 0 and 1;

Adding the probabilities: 0 + 0.3 + 0.1 + 0.3 + 0.3 = 1

Therefore, this model is a valid probability distribution model.

B) They are discrete because each value correspond to a finite number of possible values.

C) Expected value is calculated by

E(X) = \Sigma xP(x)

E(X) = 0.0 + 1*0.3 + 2*0.1 + 3*0.3 + 4*0.3

E(X) = 2.6

D) P(X=3) = P(3), which means probability of 3:

P(X=3) = 0.3

E) P(X<4): probabilities of values of X that are less than 4:

P(X<4) = P(0) + P(1) + P(2) + P(3)

P(X<4) = 0 + 0.3 + 0.1 + 0.3

P(X<4) = 0.7

F) P(X>0) = P(1) + P(2) + P(3) + P(4)

P(X>0) = 0.3 + 0.1 + 0.3 + 0.3

P(X>0) = 1

G) P(X=5) = P(5)

There is no probability of P(5) because the model doesn't "cover" that number.

H) P(X=0) = P(0)

P(X=0) = 0

I) The total area of any density curve is 1 because it represents all the possible values a variable can assume.

3 0
3 years ago
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