Answer:
Y' = -xsin(2x) + 2cos(2x)
Step-by-step explanation:
For this problem, we will need to use the product rule since you have two terms that contain the variable x.
The product rule is simply as follows:
The derivative of the function is the product of the first term times the derivative of the second term plus the derivative of the first term times the second term.
Note the derivative of 2x with respect to x, is 2.
Note the derivative of cos(2x) with respect to x is (-1/2) sin(2x).
With this in mind, let's find the derivative of our function with respect to x.
Y = 2xcos2x
Y = 2x * cos(2x)
Y' = 2x * (-1/2)sin(2x) + 2 * cos(2x)
Y' = (2x * -1 / 2) sin(2x) + 2 * cos(2x)
Y' = (-x)sin(2x) + 2cos(2x)
So the derivative of our function is Y' = -xsin(2x) + 2cos(2x) according to the application of the product rule.
Cheers.
X + number = 114
Make sure x is 50
Then switch it and
X + number = 50
Make sure it’s 14
Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
<em>(x₁, y₁)</em><em> - point on a line</em>
<em>m</em><em> - slope</em>
<em />
We have
Substitute:
Convert to the standard form
<em> use the distributive property</em>
<em>add 5 to both sides</em>
<em>add 4x to both sides</em>
Answer:
Pretty sure it's the first one. It's the only one with the correct y-intercept and has a positive slope.
This is in fancy form, so you want to simplify it:
y = 3/4(x+4) - 6
Multiply it all,
y = 3/4x + 3/4(4) - 6
y = 3/4x + 3 - 6
y = 3/4x - 3
The first one matches.
Answer:
R(x) = -0.05x^2 +80x
Step-by-step explanation:
Given the two points (x, p), the equation for the price associated with a given demand quantity can be written using the 2-point form:
p = (p2 -p1)/(x2 -x1)(x -x1) +p1
p = (40 -50)/(800 -600)(x -600) +50
p = -0.05x +80 . . . . simplify
Then the revenue equation is ...
R(x) = xp
R(x) = -0.05x^2 +80x
