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Vlad [161]
3 years ago
9

Please help me!!! (the answer isn't 140 or 70 :/ )

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

b=40

Step-by-step explanation:

Since PQ is equal to RQ triangle PQR is isosceles. Angle PRQ is equal to 40 degrees because of supplementary angles. And since triangle PQR is isosceles angle b is equal to angle PRQ which means angle b is equal to 40

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Use point-slope form to write the equation of a line that passes through the point
Ymorist [56]

Answer:

y= -2x-22.

Step-by-step explanation:

1) the slope-interception common form is y=s*x+i, where 's' and 'i' are the slope and interception, unknown numbers;

2) if x₁= -3; y₁= -16, and s=-2, then the equation of the required line can be written in the point-interception form y-y₁=s(x-x₁); ⇔ y+16= -2(x+3);

3) the required equation in slope-interception form is:

y+16= -2x-6; ⇒ y= -2x-22.

note, the provided solution is not the only and shortest way.

5 0
2 years ago
Linear function need help ASAP
ElenaW [278]

Answer:

y=1/3x+2

Step-by-step explanation:

Because it is linear equation in 2 variables

4 0
3 years ago
Read 2 more answers
Please help me with this one
lara31 [8.8K]

Answer:

D

Step-by-step explanation:

D, it has a right angle and it shows us that the hypotenuse is congruent and the leg is also congruent.

7 0
3 years ago
I need answers plzzzzz
blondinia [14]
9. Wrong name for this angle: <2
10. Wrong name for this angle: <3
5 0
3 years ago
..................................
yanalaym [24]

Answer:

The answer is a² .

Step-by-step explanation:

You have to substitute x and y into the expression :

let \: x = a \cos(θ) \\ let \: y = a \sin( θ)

{x}^{2}  +  {y}^{2}  =  {(a \cosθ )}^{2}  +  {(a \sinθ) }^{2}

{x}^{2}  +  {y}^{2}  =  {a}^{2}( {cos}^{2}θ) +  {a}^{2} ({sin}^{2}θ)

Next, you have to apply Basic Trigonometric Identity :

{sin}^{2} θ +  {cos}^{2} θ = 1

{x}^{2}  +  {y}^{2}  =  {a}^{2} ( {cos}^{2} θ +  {sin}^{2} θ)

{x}^{2}  +  {y}^{2}  =  {a}^{2} (1)

{x}^{2}  +  {y}^{2}  =  { a}^{2}

8 0
3 years ago
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