Explain why a positive discriminant results in two real solutions.

Mathematics

1 answer:

melamori03 [73]3 years ago

5 0

Answer:

Step-by-step explanation:

If the discriminant b^2 - 4ac > 0, then the two solutions are

$\frac{-b +- \sqrt{b^2 - 4ac} }{2a}$ , and in both cases, the value on the square root is > 0, so the result will always be a real number.

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Step-by-step explanation:

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