Explain why a positive discriminant results in two real solutions.
1 answer:
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Answer:
Option A is correct
The function has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;
Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;