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zvonat [6]
3 years ago
11

Explain why a positive discriminant results in two real solutions.

Mathematics
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

Step-by-step explanation:

If the discriminant b^2 - 4ac > 0, then the two solutions are

\frac{-b +- \sqrt{b^2 - 4ac} }{2a}, and in both cases, the value on the square root is > 0, so the result will always be a real number.

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