Question

Geometry help! Find part B

Answer 1

Answer:

45/4

Step-by-step explanation:

Notice that side $b$ is a leg ot the triangle at the right side, the hypothenuse is $z$ and the other leg is $y$.

We know by given that $a+b=15$, where $a+b$ is the hypothenuse of the bigger right triangle, and $z$ and $x$ are the legs. Using trigonometric reasons, we have

$cos(30\°)=\frac{z}{15}$

But, $cos(30\°)=\frac{\sqrt{3} }{2}$

Then,

$\frac{\sqrt{3} }{2} =\frac{z}{15}\\ z=\frac{15\sqrt{3} }{2}$

Then, in the triangle at the right side

$cos(30\°)=\frac{b}{\frac{15\sqrt{3} }{2} } \\\frac{\sqrt{3} }{2} =\frac{b}{\frac{15\sqrt{3} }{2} } \\\frac{\sqrt{3} }{2}=\frac{2b}{15\sqrt{3} } \\15\sqrt{3} \sqrt{3} =4b\\4b=15\times 3\\b=\frac{45}{4}$

Therefore, the answer is 45/4.

Answer 2

Answer: It looks like Part B is about 4 times that of part A.

Step-by-step explanation: I think the answer would be 12.

A would be 3. B would be 12.

I'm terribly sorry if it is wrong.