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faltersainse [42]
3 years ago
10

Geometry help! Find part B

Mathematics
2 answers:
maxonik [38]3 years ago
7 0

Answer:

<h2>45/4</h2>

Step-by-step explanation:

Notice that side b is a leg ot the triangle at the right side, the hypothenuse is z and the other leg is y.

We know by given that a+b=15, where a+b is the hypothenuse of the bigger right triangle, and z and x are the legs. Using trigonometric reasons, we have

cos(30\°)=\frac{z}{15}

But, cos(30\°)=\frac{\sqrt{3} }{2}

Then,

\frac{\sqrt{3} }{2} =\frac{z}{15}\\ z=\frac{15\sqrt{3} }{2}

Then, in the triangle at the right side

cos(30\°)=\frac{b}{\frac{15\sqrt{3} }{2} } \\\frac{\sqrt{3} }{2} =\frac{b}{\frac{15\sqrt{3} }{2} } \\\frac{\sqrt{3} }{2}=\frac{2b}{15\sqrt{3} } \\15\sqrt{3} \sqrt{3} =4b\\4b=15\times 3\\b=\frac{45}{4}

Therefore, the answer is 45/4.

hram777 [196]3 years ago
3 0

Answer: It looks like Part B is about 4 times that of part A.

Step-by-step explanation: I think the answer would be 12.

A would be 3. B would be 12.

I'm terribly sorry if it is wrong.

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