All categories

3 years ago

A number that can be written as a fraction?

Mathematics

1 answer:

WITCHER [35]3 years ago

7 0

Answer:

Rational Numbers

Step-by-step explanation:

You might be interested in

Help me please help me

noname [10]

Answer:

hello tho question is

5 hours

4 0

3 years ago

What is √7 rounded to the nearest hundredth?

Rama09 [41]

Answer:

2.64

Step-by-step explanation:

The sqhate root of 7 is 2.64575131106. Usually this would be 2.64 when rounded to nearest hundredth.

4 0

3 years ago

Five students are running for Junior class president. They draw straws to see who will go first, second, etc. In how many differ

SpyIntel [72]

<h3>Answer: 120</h3>

===================================================

Explanation:

There are 5 choices for the first selection, 4 choices for the second, etc etc until we reach 1 for the last selection. We have the countdown {5,4,3,2,1}. We'll multiply those values together to get our answer.

5*4*3*2*1 = 120

This operation of starting with some integer, counting down and multiplying along the way, is done so very often that it's given a name which is "factorial". The shorthand notation is to use an exclamation mark. So we'd say 5! = 120

6 0

3 years ago

Use the substitution method to solve the system of equations. Choose the correct ordered pair. 2x + y = 10 y = x – 5 A. (5, 0) B

erica [24]

It would be A.) (5,0)

8 0

3 years ago

Read 2 more answers

(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi

Drupady [299]

Answer:

a. $\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. $x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. $c = \dfrac{3}{8} \ g/L$

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx = (5·c - 5·c/3)×dt = 20/3·c = $6\frac{2}{3} \cdot c \cdot dt$

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. The amount of salt, x after t minutes is given by the relation

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

$dx = 6\frac{2}{3} \cdot c \cdot dt$

$x(t) = \int\limits \, dx = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt$

$x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

$x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10$

$6\frac{2}{3} \times c =\dfrac{25 \ grams }{10}$

$c =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} } = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200} \ g/L = \dfrac{3}{8} \ g/L$

$c = \dfrac{3}{8} \ g/L$

4 0

3 years ago