There isnt enough information to answer the question, the missing variable is "distance from said falling spot and ground"
Answer:
Explanation:
Given
Sphere A has a net charge of +5 Q
Sphere B has a net charge of -3 Q
Sphere C has a net charge of 7 Q
When sphere B is touched to sphere A then charge is redistributed among the sphere such that charge on each sphere is
Now sphere A and B has charge Q
When sphere A is touched to sphere C
Net charge after removal
Now sphere A and C has 4 Q charge
Now sphere C and B is touched
Net charge on C and B is given by
At the end of process charge on sphere A is 4Q
Charge on B and C is 2.5Q
Answer:
Explanation:
gauge pressure due to a liquid column of density d and height h is given by the following expression .
P = hdg
The pressure depends upon height of liquid column and not on the cross sectional area .
In first cylinder .
gauge pressure = .40 atm
hdg = .40 atm
cross sectional area of cylinder = π r²
The radius of second cylinder is twice of the first , cross sectional area will be 4 times .
The volume remains the same when the liquid is poured into second cylinder
volume = cross sectional area x height .
As cross sectional area of second cylinder is 4 times , height of liquid column in second cylinder = h / 4 .
gauge pressure in second cylinder = h / 4 x d x g = hdg / 4
.40 / 4 = .10 atm
gauge pressure in second cylinder = .10 atm.
Use the Second Law of Newton, which states that Net Force = mass times acceleration
F = m * a
F = 50 kg * 1.5 m/s^2 = 75 N
Answer: option C