What will happen if our atmosphere was oxygen

If there are oncoming cars to the left of you and a child on a bike to the right, what is the correct action to take

tankabanditka [31]

Answer:

Give the child a lot of room to your side, which may mean moving closer to the oncoming vehicles.

Explanation:

I majored in Physics.

3 0

2 years ago

A roller coaster has a vertical loop with radius 25.7 m. With what minimum speed should the roller-coaster car be moving at the

gogolik [260]

Answer:

15.88m/s

Explanation:

At the top of the roller coaster you will have three forces acting on the roller-coaster. See the image below. Fc is the centripetal force (for an object in circular motion), Fg is the gravitational force, and Fn is the normal force. To achieve the minimum speed we assume the roller-coaster is barely touching the vertical loop and so the normal force is zero. This leaves two acting forces.

$F_g = F_c\\mg = \frac{m\times v^2}{r}\\v = \sqrt{gr} = \sqrt{9.81 \times 25.7} = 15.88 m/s$

7 0

2 years ago

1. a) What equal amount of positive charge would have to be placed on the Earth and on the Moon to neutralize their gravitationa

Paul [167]

Answer:

A) q = 5.714 × 10^(13) C

B) Because from a above, F_e = F_g and so r² canceled out in the formulas

C) m_t = 5.964 × 10⁴ kg

Explanation:

For the gravitational attraction of the earth and moon to be neutralized, the electrostatic force must be equal to the gravitational force i.e F_e = F_g

Now, F_e = kq²/r² and F_g = GmM/r²

Equating them and making q the subject, we arrive at;

q = √(GmM/k)

Where;

G is gravitational constant = 6.67 × 10^(-11) m³/kg.s²

m is mass of moon = 7.36 × 10^(22) kg

M is mass of earth = 5.98 × 10^(24) kg

k is coulombs constant = 8.99 x 10^(9) N.m²/c²

q = √(6.67 × 10^(-11) × 7.36 × 10^(22) × 5.98 × 10^(24)/8.99 x 10^(9))

q = 5.714 × 10^(13) C

B) We don't need the lunar distance because from a above, F_e = F_g and so r² canceled out in the formulas.

C) The number of protons is given by the formula;

n = q/e

Where, e is charge of the proton = 1.6 × 10^(-19) C

n = (5.714 × 10^(13))/(1.6 × 10^(-19))

n = 3.57125 × 10^(32)

Total mass of these protons is given by the formula;

m_t = nm_p

Where m_p is mass of a single proton = 1.67 × 10^(-27) kg

m_t = 3.57125 × 10^(32) × 1.67 × 10^(-27)

m_t = 5.964 × 10⁴ kg

5 0

2 years ago

A light ray in air is incident on a transparent material whose index of refraction is t. o. Find an expression for the (non-zero

vovangra [49]

Answer:

Explanation:

Refractive index f the medium, n = t

Let the angle of incidence is i

(a) As given in the question, the angle of refraction is half of angle of incidence.

Let the angle of refraction is r

r = i / 2

By use of Snell's law

$n = \frac{Sin i}{Sin r}$

By substituting the values, we get

$t = \frac{Sin i}{Sin \frac{i}{2}}$

By using the formula of trigonometry

Sin2Ф = 2 SinФ CosФ

So, $t = \frac{2Sin \frac{i}{2}\times Cos\frac{i}{2}}{Sin \frac{i}{2}}$

$t = 2Cos\frac{i}{2}$

(b) For glass, the value of refractive index is 1.5, so the above expression becomes

$1.5 = 2Cos\frac{i}{2}$

$Cos\frac{i}{2}=0.75$

$\frac{i}{2}=41.4$

i = 82.8°

8 0

3 years ago

State two main assumption of the kinetic theory of gases

Tomtit [17]

The simplest kinetic model is based on the assumptions that: (1) the gas is composed of a large number of identical molecules moving in random directions, separated by distances that are large compared with their size; (2) the molecules undergo perfectly elastic collisions (no energy loss) with each other and with the

5 0

3 years ago