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3 years ago

The North Star is located in the Big Dipper. True or False

Physics

2 answers:

harina [27]3 years ago

4 0

Answer:

False

Explanation:

It is located in the little dipper whose stars are more faint.

Maurinko [17]3 years ago

4 0

False, the North Star is located at the end of the handle of the Little Dipper, as opposed to the Big Dipper. Hope this helps!

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Sound is a type of _____ wave.

saul85 [17]

Sound is an example of a mechanical wave. Mechanical waves are the kinds of waves that cannot be propagated without a medium. As such, these waves cannot travel through a vacuum, just like how sound cannot travel through space, since space is a vacuum.

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3 years ago

What are the relative ages of the features in order of oldest to youngest?

yuradex [85]

Answer:

Layer 1, Rock 2, Rock 1, Fault

8 0

3 years ago

Electromagnetic waves differ from the other types of waves because they are

Ronch [10]

Correct answer choice is :

B) Able to travel through a vacuum.

Explanation:

Electromagnetic waves are applied to carry long/short/FM wavelength radio waves, and TV/telephone/wireless signals or services. They are also effective for transferring energy in the form of microwaves, infrared radiation, visible light, ultraviolet light, X-rays, and gamma rays. Electromagnetic waves change from mechanical waves in that they do not need a medium to generate. This means that electromagnetic waves can move not only in the air and solid matters but also in the void of space.

Read more on Brainly.com - brainly.com/question/1697984#readmore

4 0

3 years ago

Read 2 more answers

In a large centrifuge used for training pilots and astronauts, a small chamber is fixed at the end of a rigid arm that rotates i

RSB [31]

a) The length of the arm of the centrifuge is 10.9 m

b) The angular acceleration is $2.7 rad/s^2$

Explanation:

In a uniform circular motion, the centripetal acceleration is given by

$a_c=\omega^2 r$

where:

$\omega$ is the angular speed of the circular motion

r is the radius of the circle

For the centrifuge in this problem, we have:

$\omega=1.7 rad/s$ is the angular speed

The centripetal acceleration is 3.2 times the acceleration due to gravity ( $g=9.8 m/s^2$ ), so:

$a_c=3.2 g = 3.2(9.8)=31.4 m/s^2$

Therefore, we can re-arrange the previous equation to find r, the radius of the circle (which corresponds to the length of the arm of the centrifuge):

$r=\frac{a_c}{\omega^2}=\frac{31.4}{1.7^2}=10.9 m$

In the second part of the exercise, the centrifuge speeds up from an initial angular speed of 0 to a final angular speed of 1.7 rad/s. The total acceleration experienced at the final moment is

$a=4.4 g$

So, 4.4 times the acceleration due to gravity.

The total acceleration is the resultant of the centripetal acceleration ( $a_c$ ) and the tangential acceleration ( $a_t$ ):

$a=\sqrt{a_c^2+a_t^2}$

We know that:

a = 4.4g

$a_c = 3.2 g$

So, we can find the tangential acceleration:

$a_t = \sqrt{a^2-a_c^2}=\sqrt{(4.4g)^2-(3.2g)^2}=29.6 m/s^2$

The angular acceleration is related to the tangential acceleration by

$\alpha = \frac{a_t}{r}$

where r = 10.9 m is the length of the centrifuge. Substituting,

$\alpha = \frac{29.6}{10.9}=2.7 rad/s^2$

Learn more about centripetal and angular acceleration here:

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8 0

3 years ago

A coin is dropped. What is its displacement after 0.30 s.

Morgarella [4.7K]

Assuming this coin is on earth and that it wasn’t dropped forcefully:
Use the formula d = 1/2at^2. Rewriting using a=g and solving for height h gets us h = 1/2(9.8)t^2.
In this case that would get that the change in height h is 0.5(9.8)(0.3^2) = 0.441 m.

3 0

3 years ago