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prohojiy [21]
4 years ago
14

A balloon holds 20.0 L of helium at 10 degree Celsius. If the temperature doubles, and the pressure does not change, what will b

e the new volume of the balloon? Using Charles's Law
Please help!
Physics
1 answer:
Natali [406]4 years ago
8 0

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 2 x 20.0/ 1

<span>V2 = 40 L </span>

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One of the efficient concepts that can help us find the number of turns of the cable is through the concept of induced voltage or electromotive force given by Faraday's law. The electromotive force or emf can be described as,

\epsilon = NBA\omega

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N = Number of loops

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A = Cross-sectional Area

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Re-arrange to find N,

N = \frac{\epsilon}{BA\omega}

Our values are given as,

\epsilon = 19V

B = 0.434T

\omega = 49.8\frac{rev}{s} (\frac{2\pi rad}{1 rev}) = 99.6\pi rad/s

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Replacing at our equation we have:

N = \frac{\epsilon}{( 0.434)A\omega}

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