How do i solve 4x - 2y = 22 and 2x + 4y = 6 using substitution and elimination?

1 answer:

5 0

substitution and elimination means that you need to use one equation and substitute it in place of some variable in the other equation.

Consider the above two equations.

Take equation 1, which is 4x-2y=22 => x=(22+2y)/4

substitute the x value gained above in equation 2.

so, 2((22+2y)/4)+4y=6

22+2y+8y=12 => 10y = -10 => y= -1.

Substitute y= -1 in x value obtained in the beginning.

So, x= (22 - 2)/4 => 5.

There fore, x= 5 and y= -1

Hope it helps.

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Answer:

$a.\hspace{3} \frac{6}{38} = 0.15789474\\\\b.\hspace{3} \frac{45}{55} = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 0.14285714\\\\d.\hspace{3} \frac{35}{28} = 1.25\\\\e.\hspace{3} \frac{1030}{2030} = 0.50738916$

Step-by-step explanation:

Rational numbers, expressed as decimal numbers, are obtained from the operation of division between the integer of the numerator and the integer of the denominator. Then:

$a.\hspace{3} \frac{6}{38} = 6\div38 = 0.15789474\\\\ b.\hspace{3} \frac{45}{55} = 45\div55 = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 4\div28 = 0.14285714\\\\ d.\hspace{3} \frac{35}{28} = 35\div28 = 1.25\\\\ e.\hspace{3} \frac{1030}{2030} = 1030\div2030 = 0.50738916$