Biotic potential and _____ determine ____

In a sample of bacterial DNA, 14% of the nitrogenous bases are thymine. About what percentages are the other nitrogenous bases?

Nookie1986 [14]

The answer is D

Explanation: You need to have the same number of complementary bases.

6 0

3 years ago

Which of the following places the steps in the PCR procedure in the correct order?

Marta_Voda [28]

Answer:

Polymerase chain reaction (PCR) test is used to duplicate traces of DNA from any living form, for identification purposes. The correct sequence is 1, 3, 2; based on the options given.

Explanation:

The steps to be followed for the PCR procedure are:

Denaturation

Option 1. Involves incubation at 94°C to denature DNA strands into single strands by breaking of weak hydrogen links

Annealing

Option 3. Temperature is lowered to 60°C to allow primers joining their similar DNA sequences.

Elongation

Option 2. Incubate at 72°C to promote the extension of the DNA strands, actually extending them.

5 0

3 years ago

assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

6 0

2 years ago

n mice, dwarfism is caused by an X-linked recessive allele, and pink coat is caused by an autosomal dominant allele (coats are n

nexus9112 [7]

Answer:

The probability of getting a dwarf and pink female is 1/2

Explanation:

In mice, dwarfism is caused by an X-linked recessive allele, and pink coat is caused by an autosomal dominant allele where coats are normally brownish.

A dwarf female from a pure line will have Xd Xd where d represent the recessive trait and the female is also brownish (pp).

A pink male from a pure line will be XPY where P represent the dominant allele but not a dwarf (D).

Xd Xd Xp Xp

XD XDXd XDXd XP XPXp XPXp F1 generation

Y XdY XdY Y XpY XpY

P XDXd x XdY XPXp x XpY

XD Xd XP Xp

Xd XDXd XdXd Xp XPXp XpXp F2 generation

Y XDY XdY Y XPY XpY

The probability of getting a dwarf and pink female is 1/2

5 0

3 years ago

What did Darwin discover about plants from his phototropism experiments?

mel-nik [20]

Answer:

https://www.biology-pages.info/T/Tropisms.html

Explanation:

This link holds all the information you need :D

7 0

3 years ago

Biotic potential and _____ determine _____.

Biotic potential and _ determine _.