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Alexxandr [17]
3 years ago
6

Give an example of what would be membrane enclosed organelles in a eukaryotic cell.​

Biology
2 answers:
Harman [31]3 years ago
4 0

Answer:

hi! there are numerous membrane-bound organelles, which include the endoplasmic reticulum, Golgi apparatus, chloroplasts, and mitochondria

Gennadij [26K]3 years ago
3 0

Answer:

Mitochondria, endoplasmic reticulum, golgi apparatus, or chloroplasts would all be an example.

Explanation:

Unlike prokaryotic cells, eukaryotic cells have a nucleus enclosed in a plasma membrane, as well as the mitochondrias, endoplasmic reticulums, golgi bodies or apparatuses, and chloroplasts.

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1. What processes that occur during meiosis contribute to
andrey2020 [161]
A and D because cytokinesis is where a single eukaryotic cell divides into two daughter cells. Gametogenesis is the name given to the process where the cell undergoes meiosis.
8 0
2 years ago
Macromolecule Suggested percentage of diet Actual percentage of diet Carbohydrates 45–65% 70% Lipids 20–35% 5% Proteins 10–35% 2
SIZIF [17.4K]
10-35%25% based on the table the decrease of the table is 25%25%.Good Luck.
5 0
3 years ago
if your fathers dominant gene was blond hair, but your mother's dominant gene was brown hair, what would the Childs hair color b
barxatty [35]

Answer:

Brown Or a Hazel color because a lot of kids come out with brown/hazel hair so I'm pretty sure Brown Or Hazel color

Explanation:

Ok

7 0
3 years ago
In a population of pea plants, 36 plants are homozygous for the dominant trait of yellow peas (YY), 48 plants are heterozygous f
baherus [9]

Answer:

The correct answer would be C. 0.60

It can be calculated with the help of Hardy-Weinberg equation i.e

p² + q² + 2pq = 1

Also, p + q = 1

  • where p represents the frequency of dominant allele.
  • q represents the frequency of recessive allele.
  • p² represents the frequency of homozygous dominant genotype .
  • q² represents the frequency of homozygous recessive genotype .
  • 2pq represents the frequency of heterozygous genotype.

Number of homozygous dominant (YY) = 36

Number of homozygous recessive (yy) = 16

Number of heterozygous dominant (Yy) = 48

Total number of plants = 100

Now, frequency of homozygous dominant (YY) = 36/100 = 0.36

Therefore, p² = 0.36

So, p = √0.36 = 0.60

Hence, frequency of dominant allele (Y) = 0.60

5 0
4 years ago
A scientist begins a PCR with 10 picograms of DNA and allows it to go through three cycles.
BaLLatris [955]

Answer:

b. 80g

Explanation:

Three cycles of PCR would produce 3 doublings of the amount of DNA.

Cycle 1: 10x2  = 20pg

Cycle 2: 20x2 = 40pg

Cycle 3: 40x2 = 80pg

This can also be worked out for large cycle numbers by final mass = starting mass x 2ⁿ, where n is the number of cycles.

5 0
3 years ago
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