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pishuonlain [190]
4 years ago
13

Solve for x.

Mathematics
2 answers:
jasenka [17]4 years ago
7 0

Answer:

Your answer is

x = -4, 6 or (b)

Have a nice day and please mark me as brainliest!! (:|

~abelxoconda

sergeinik [125]4 years ago
4 0

Answer:

your answer will be B. -4,6

Step-by-step explanation:

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155% of what number is 44? No decimals, rounding, or mixed numbers. ​
Archy [21]

Answer:

It is 68.2, thats the answer

Step-by-step explanation:

If you want no rounded just the main number it is 68

4 0
3 years ago
Read 2 more answers
I Need help please!!!
lisov135 [29]
Just use substitution, y intercept is 3 so it would be 3= -2(5) I’m not an expert but I tried.
8 0
3 years ago
Please answer this friends​
lakkis [162]

Answer: 6/9

Step-by-step explanation:

1) 2/3 + 3/4=5/7

2) 1/2+5/7=6/9

3) Did this help

5 0
3 years ago
PLZ HELP!! A die is rolled. What is the probability of rolling a 2 or a 6? >>Also, is this an mutually exclusive or inclus
Nutka1998 [239]
The probability would be 2/6, or 1/3 if you were to reduce the fraction.
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3 years ago
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Which equation has the solutions x = startfraction negative 3 plus-or-minus startroot 3 endroot i over 2 endfraction? 2x2 6x 9 =
Gennadij [26K]

The quadratic equation which matches given solution is x² + 3x + 3 = 0. Then the correct option is C.

<h3>What is a quadratic equation?</h3>

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

We know that the formula

\rm x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

The solutions are given below.

\rm x = \dfrac{-3 \pm \sqrt3 \iota }{2}

Then

1)  2x² + 6x + 9 = 0, the zeroes of the equation will be

\rm x = \dfrac{-6\pm 6\iota}{4}\\\\x = \dfrac{-3\pm 3 \iota}{2}

2)  x² + 3x + 12 = 0, the zeroes of the equation will be

\rm x = \dfrac{-3\pm \sqrt{39}\iota}{2}

3)  x² + 3x + 3 = 0, the zeroes of the equation will be

\rm x = \dfrac{-3\pm \sqrt3\iota}{2}

4)  2x² + 6x + 3 = 0, the zeroes of the equation will be

\rm x = \dfrac{-6\pm 2\sqrt{3}}{4}\\\\x = \dfrac{-3\pm \sqrt3 }{2}

More about the quadratic equation link is given below.

brainly.com/question/2263981

4 0
2 years ago
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