No two <em>intergers</em> can solve this problem. If you're not in Algebra II yet, the answer is probably "none."
Just look at the factor pairs of 25:
1 × 25
-1 × 25
5 × 5
-5 × -5
Clearly none of those can add up to 6.
If you want the more complex answer, I'll show you how here. If you don't understand why it doesn't work, that's okay. I just want you to see that there's not an actual answer to the problem.
a+b = 6
a = 6-b
ab = 25
(6-b)b = 25
6b -b² = 25
-b² + 6b = 25
b² -6b = -25
Factor by splitting the middle.
Half of -6 is -3, (-3)² = 9. Add this to each side.
b² -6b + 9 = -16
Factor the perfect square trinomial.
(b-3)² = -16
Take the square root of each side.
b-3 = 4i
b = 3+4i
a+b = 6
a+3+4i = 6
a= 3-4i
<em>(The "i" stands for an imaginary number, specifically, the square root of -1.)</em>
Answer:
64
Step-by-step explanation:
Hope it helps!
Answer: number two
Step-by-step explanation: i really hope this helps
<h2>
Answer:</h2>
The image to the question is missing, but I found a matching image, which is attached to this solution
Answer:
3 minutes = 13 dots
100 minutes = 401 dots
t minutes = 4(t) + 1 dots
Step-by-step explanation:
From the image, the following can be noticed:
time (Mins) dots
0 1
1 5
2 9
The pattern gotten from this progression is that, if the time is multiplied by 4, and the result added to one, the result will be the number of dots.
hence, when the time is 0 minutes:
0 × 4 = 0
0 + 1 = 1 ( 1 dot)
when the time is 1 minute
1 × 4 = 4
4 + 1 = 5 (5 dots)
when the time is 2 minutes
2 × 4 = 8
8 + 1 = 9 ( 9 dots)
Therefore,
when the time = 3 minutes
3 × 4 = 12
12 + 1 = 13 dots
at 100 minutes:
100 × 4 = 400
400 + 1 = 401 dots
at t miutes
t × 4 = 4t
4t + 1 = number of dots
Therefore number of dots at t minutes = 4(t) + 1