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Likurg_2 [28]
4 years ago
10

An object with a mass of 3.0 g raises the level of water in a graduated cylinder from 25.1 mL to 33.1 mL. What is the density of

the object?
Mathematics
1 answer:
evablogger [386]4 years ago
7 0
The displaced volume of the water, because of the submersion of the object, is equal to the volume of the object.

So to find the volume of the object we calculate the difference in volume of water:
33.1-25.1 = 8 ml

Since 1 mL of water has the volume of  1cm^3, then the volume of the object is 8 cm^3.


The density of the object is found by the formula:

density= mass/volume= (3 g) / (8 cm^3) = 3/8 (g/cm^3)= 0.375 g/cm^3


Answer: 0.375 g/cm^3
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The algebraic expression for the difference between the squares of the two numbers, supposing the two numbers to be a and b, is

a² - b² = (a + b)(a - b).

An algebraic expression is a combination of terms, where the terms are separated using mathematical operators like plus (+), minus (-), multiply (*), and divide (/).

The terms are combinations of numerals and variables.

Variables are represented alphanumerically, which can hold any value as per the expression they are used in.

In the question, we are asked to write the algebraic expression for the difference between the squares of two numbers.

We assume the two numbers to be a and b respectively.

Thus, we are asked to write an expression for the difference between the square of a and square of b, that is, we are asked to write an expression for a² - b².

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