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solong [7]
4 years ago
5

How do you solve 4x+5<-6

Mathematics
1 answer:
Bogdan [553]4 years ago
7 0

After solving 4x+5 we get x

Step-by-step explanation:

We need to solve the inequality:

4x+5

Solving:

Adding -5 on both sides

4x+5

So, after solving 4x+5 we get x

Keywords: Solving the inequality

Learn more about solving the inequality at:

  • brainly.com/question/1858613
  • brainly.com/question/11788572
  • brainly.com/question/1465430

#learnwithBrainly

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Find the fourth roots of 256(cos 280° + i sin 280°).
VladimirAG [237]

Step-by-step explanation:

answer

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5 0
3 years ago
Help me plsssssssss its easy and show work please
babymother [125]

Answer:

» For x-intercept, y is zero

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>1</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>3</u><u>2</u><u> </u>

{ \tt{0 =  {x}^{2} - 12x + 32 }} \\ { \tt{ {x}^{2} - 12x + 32 = 0 }} \\ { \tt{(x - 8)(x - 4) = 0}} \\ { \tt{x = 8 \:  \: and \:  \: 4}} \\  { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: (8, \: 0) \:  \: and \:  \: (4, \: 0) \:  \: }}}

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>1</u><u>0</u><u>x</u><u> </u><u>+</u><u>2</u><u>4</u><u> </u><u>:</u>

{ \tt{0 =  {x}^{2}  - 10x + 24}} \\ { \tt{ {x}^{2}  - 10x + 24 = 0}} \\ { \tt{(x - 6)(x - 4) = 0}} \\ { \tt{x = 6 \:  \: and \:  \: 4}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: (6, \: 0) \:  \: and \:  \: (4, \: 0) \:  \: }}}

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{ \tt{0 =  {x}^{2}  + 10x + 16}} \\ { \tt{ {x}^{2} + 10x + 16 = 0 }} \\ { \tt{(x + 2)(x + 8) = 0}} \\ { \tt{x =  - 2 \:  \: and \:  \:  - 8}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: ( - 2, \: 0) \:  \: and \:  \: ( - 8, \: 0) \:  \: }}}

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>2</u><u>5</u><u> </u><u>:</u>

{ \tt{0 =  {x}^{2}  - 25}} \\ { \tt{ {x}^{2}  = 25}} \\ { \tt{ \sqrt{ {x}^{2}  } =  \sqrt{25}  }} \\ { \tt{x =  \pm5}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: (5, \: 0) \:  \: and \:  \: ( - 5, \: 0) \:  \: }}}

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{ \tt{0 =  {x}^{2} + 8x + 12 }} \\ { \tt{ {x}^{2} + 8x + 12 = 0 }} \\{ \tt{(x + 2)(x + 6) = 0}} \\ { \mathfrak{x - intercept :  \:  \: }}{ \boxed{ \tt{ \: ( - 2, \: 0) \:  \: and \:  \: ( - 6, \: 0) \:  \: }}}

8 0
3 years ago
-3(4x+3)+4(6x+1)=43 how do I solve it
Gala2k [10]
Solve for x:
4 (6 x + 1) - 3 (4 x + 3) = 43
-3 (4 x + 3) = -12 x - 9:
-12 x - 9 + 4 (6 x + 1) = 43
4 (6 x + 1) = 24 x + 4:
24 x + 4 - 12 x - 9 = 43
Grouping like terms, 24 x - 12 x - 9 + 4 = (24 x - 12 x) + (4 - 9):
(24 x - 12 x) + (4 - 9) = 43
24 x - 12 x = 12 x:
12 x + (4 - 9) = 43
4 - 9 = -5:
12 x + -5 = 43
Add 5 to both sides:
12 x + (5 - 5) = 5 + 43
5 - 5 = 0:
12 x = 43 + 5
43 + 5 = 48:
12 x = 48
Divide both sides of 12 x = 48 by 12:
(12 x)/12 = 48/12
12/12 = 1:
x = 48/12
The gcd of 48 and 12 is 12, so 48/12 = (12×4)/(12×1) = 12/12×4 = 4:
Answer:  x = 4
3 0
4 years ago
(20 points!) (photo attached for context)<br> Line segment ST is congruent to which line segment?
Brrunno [24]
Opposites seem to me congruent in the image so reflect that across.
Line ST is congruent to UT
6 0
2 years ago
a rectangular school gym has a length of x+14 and a width of x-20 which measure does (x+14)(x-20) represent
Vinil7 [7]
The area, which is L x W.
L = x+14
W = x-20
Therefore, LW or (x+14)(x-20) is the area
8 0
4 years ago
Read 2 more answers
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