Question

In December, Sarah's website had 72,000 visitors. In December of the previous year it had 51,500 visitors. Find the percentage to the nearest tenth of a percent in the number of visitors her website had for that year

Answer 1

In December, Sarah's website had 72,000 visitors. In December of the previous year it had 51,500 visitors.

Percentage increase = $\frac{population(present) - popilation(last year)}{population(last year)}$ * 100

Visitors in present year = 72000

Visitors in previous year = 51500

Increase in the number of visitors = 72000 - 51500 = 20500

Percentage increase = $\frac{72000) - 51500}{51500}$ * 100

= $\frac{20500}{51500} * 100$

= 39.80582 %

So the percent of increase in number of visitors = 39.8%