It is true because protons are positively charged and electrons are negatively charged. if there is the same number of protons and electrons, both charges cancel out.
The relation between the volume of the gas and the temperature is established by Charles's law. With a decrease in the temperature, the volume decreases by 45.7 mL. Thus, option c is correct.
<h3>What is Charle's law?</h3>
Charle's law states the direct relation present between the temperature and the volume of the gas. The law is given as:
V₁ ÷ T₁ = V₂ ÷ T₂
Given,
V₁ = 50 mL
T₁ = 303.15 K
T₂ = 277.15 K
Substituting the value the final volume is calculated as:
50 ÷ 303.15 = V₂ ÷ 277.15
V₂ = (50 × 277.15) ÷ 303.15
= 45.71 mL
Therefore, option c. 45.7 mL is the final volume.
Learn more about Charles law here:
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Answer:
15 g/mol
Explanation:
If you need to round 14.8232 g/mol down to 2 significant figures, you start on the left, count in two (14) and round with the next number (.8).
Because 8 is higher than 4, you round up, getting the answer 15.
Regards!
Boyle's law, which summarizes these observations, states that: the volume of a certain amount of gas, which is maintained at a constant temperature, is inversely proportional to the pressure exerted, which is summarized in the following expression:
P.V = constant or P = 1 / V
Example:
An inflated balloon with a volume of 0.55L at sea level (1.0 atm) is allowed to rise to a height of 6.5 km, where the pressure is about 0.40 atm.
Assuming that the temperature remains constant, what is the final volume of the balloon?
Reasoning and solution:
Note that the number of moles and the temperature of the gas remain constant, so Boyle's law is used. From the equation:
P1V1 = P2 V2
Where P1 = 1 atm, V1 = 0.55L and P2 = 0.40 atm, as well
V2 = V1 x (P1 / P2) = 0.55 L x (1 atm / 0.40 atm) = 1.4 L
When the pressure is reduced (at a constant temperature), the volume increases. The final volume is greater than the initial volume, so the answer is reasonable.
<h3>Heya</h3><h3>Here is your answer</h3><h3>________________</h3><h3></h3><h3>A temperature of 20°C is equivalent to approximately 68 degree Fahrenheit (standard room temperature).</h3><h3></h3><h3>==================</h3><h3></h3><h3>Hope this helped!!!</h3><h3>Happy to help :)</h3>