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Vsevolod [243]
3 years ago
10

Is there any evidence that methanol forms ions either in the pure state or when dissolved in water?

Chemistry
1 answer:
worty [1.4K]3 years ago
3 0
According to research, the answer is no. Although alcohol is dissolves in water solution but dissociation of methyl alcohol in into ions is barely not possible. Thus, methanol is considered as a non-electrolyte.
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Which ion in the ground state has the same electron configuration as an atom of
Sergeu [11.5K]

Answer:

Ca^+2

Explanation:

Hence, the correct option is A.

4 0
3 years ago
3. What is the energy of a photon whose frequency is 5.2 x 1015 Hz? Use the equation: E = hxv
anzhelika [568]

Answer:

3. 3.45×10¯¹⁸ J.

4. 1.25×10¹⁵ Hz.

Explanation:

3. Determination of the energy of the photon.

Frequency (v) = 5.2×10¹⁵ Hz

Planck's constant (h) = 6.626×10¯³⁴ Js

Energy (E) =?

The energy of the photon can be obtained by using the following formula:

E = hv

E = 6.626×10¯³⁴ × 5.2×10¹⁵

E = 3.45×10¯¹⁸ J

Thus, the energy of the photon is 3.45×10¯¹⁸ J

4. Determination of the frequency of the radiation.

Wavelength (λ) = 2.4×10¯⁵ cm

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm

2.4×10¯⁵ cm = 2.4×10¯⁷ m

Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m

Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:

Wavelength (λ) = 2.4×10¯⁷ m

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

v = c / λ

v = 3×10⁸ / 2.4×10¯⁷

v = 1.25×10¹⁵ Hz

Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.

8 0
3 years ago
Which of the following statements is NOT a part of John Dalton's atomic theory?
Goshia [24]

The statement that is NOT a part of John Dalton's atomic theory Electrons move in specific orbits around the nucleus of an atom. The statements ‘All elements are composed of atoms that cannot be divided’, ‘All atoms of the same element are exactly alike and have the same mass’ and ‘Every compound is composed of atoms of different elements, combined in a specific ratio’ are not his theory.

7 0
3 years ago
You have prepared a 1.0 M solution of CaCl2 in the laboratory.
Ratling [72]
It’s C I think and I’m not sure
6 0
3 years ago
How many grams of Al(OH)3 are produced from 3.00 g of AlCl3 with excess of NaOH?
Blizzard [7]

Answer:

1.772 gram is the approximate answer

Explanation:

molecular mass of AlCl3 is 132 g per mole and of Al(OH)3 is 78 g per mole

the reaction is

AlCl3 + 3 NaOH ---> Al(OH)3 + 3 NaCl

from the reaction it is clear that 1 mole AlCl3 makes 1 mole Al(OH)3

implies 132g AlCl3 gives 78g Al(OH)3

Implies 3g AlCl3 gives

3*122/78 = 1.772 grams

3 0
3 years ago
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