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Vsevolod [243]
3 years ago
10

Is there any evidence that methanol forms ions either in the pure state or when dissolved in water?

Chemistry
1 answer:
worty [1.4K]3 years ago
3 0
According to research, the answer is no. Although alcohol is dissolves in water solution but dissociation of methyl alcohol in into ions is barely not possible. Thus, methanol is considered as a non-electrolyte.
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I NEED HELP :)
BlackZzzverrR [31]

Answer:

48 mph

Explanation:

total time= 19/12 hr

distence- 76 miles

speed- D/T=76/19/12

which is 48mph

if my answer helps please mark as brainliest.

8 0
3 years ago
Read 2 more answers
Is the pressure, volume, and temperature of a gas are know, which can most likely be found by using the ideal gas law?
Fiesta28 [93]

The molar amount of gas can most likely be found by using the ideal gas law. This is because the ideal gas law states pV = nRT. P, V, and T are the pressure, volume, and temperature, which are the known variables. The R stands for the Universal Constant of Gases; also known. Therefore, the unknown is n, the number of moles (molar amount) of gas, and so you would solve for n from the law.

Answer: A) The molar amount of gas

Credit to: @Edufirst

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there is still good to live for

8 0
4 years ago
(a) Find the concentration of electrons and holes in a sample of germanium that has a concentration of donor atoms equal to 1015
matrenka [14]

Answer:

a) Germanium = 5.76 x 〖10〗^11 〖cm〗^(-3) , Semiconductor is n-type.

b) Silicon = 2.25 x 〖10〗^5 〖cm〗^(-3) , Semiconductor is n-type.

For clear view of the answers: Please refer to calculation 5 in the attachments section.

Explanation:

So, in order to find out the concentration of holes and electrons in a sample of germanium and silicon which have the concentration of donor atoms equals to 〖10〗^15 〖cm〗^(-3). We first need to find out the intrinsic carrier concentration of silicon and germanium at room temperature (T= 300K).

Here is the formula to calculate intrinsic carrier concentration: For calculation please refer to calculation 1:

So, till now we have calculated the intrinsic carrier concentration for germanium and silicon. Now, in this question we have been given donor concentration (N_d) (N subscript d), but if donor concentration is much greater than the intrinsic concentration then we can write: Please refer to calculation 2.

So, now we have got the concentration of electrons in both germanium and silicon. Now, we have to find out the concentration of holes in germanium and silicon (p_o).  (p subscript o)

Equation to find out hole concentration: Please refer to calculation 3. and Calculation 4. in the attachment section.

Good Luck Everyone! Hope you will understand.  

6 0
3 years ago
Which pair shares the same empirical formula? (
morpeh [17]
The pair thats right
4 0
3 years ago
Cuanto equivale 1000 yardas a 1 pie, 1 metro y 1 centímetro
Charra [1.4K]

Respuesta:

3000 ft

914.4 m

9.144 × 10⁴ cm

Explicación:

Paso 1: Información provista

Longitud: 1000 yd

Paso 2: Convertir 1000 yd a pies (ft)

Usaremos el factor de conversion 1 yd = 3 ft.

1000 yd × 3 ft/1 yd = 3000 ft

Paso 3: Convertir 1000 yd a metros (m)

Usaremos el factor de conversion 1 yd = 0.9144 m.

1000 yd × 0.9144 m/1 yd = 914.4 m

Paso 4: Convertir 914.4 m a centimetros (cm)

Usaremos el factor de conversion 1 m  = 100 cm.

914.4 m × 100 cm/ 1 m = 9.144 × 10⁴ cm

5 0
3 years ago
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