Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test

Formula : 


Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
The denominator is 4 and the numerioar to make factor 1/2 would be 4/8 then 1/2
Answer:
Coordinates for B= (10,-2)
Step-by-step explanation:
The solution is shown in the image provided step by step, as it was not possible typing it on this given space here. Hope it helps :)
I uploaded the answer to a file hosting. Here's link:
cutt.us/brainly