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3 years ago

What is the center of the circle? Please show steps!

Mathematics

1 answer:

Vika [28.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the equation:

$x^2+(y-4)^2=25\\\\(x-0)^2+(y-4)^2=5^2$

h = 0, k = 4, r = 5

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I would love help and thank you

tigry1 [53]

The formula is width times length

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2 years ago

Read 2 more answers

Write an equation of the line with the given slope and y intercept: m = 2, b = - 3/4

Alex

Answer:

y = 2x - 3/4

Step-by-step explanation:

Adapt the slope-intercept form: y = mx + b.

Making the indicated substitutions, we get

y = 2x - 3/4

4 0

3 years ago

Draw a line plot for the fallowing data measured in inches

sladkih [1.3K]

Here you go I hope I helped

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3 years ago

I need work shown please help (I will mark as brainliest)

JulsSmile [24]

Answer:

for the second page the answer is B the third page is D

Step-by-step explanation:

15 x 10 x 8 = 1200

24 + 25 (49 + 64 + 55)= 168

Hope this helps
i could only give you two of them
Brainliest plz
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7 0

3 years ago

Cubed root x cubed root x2

Yuki888 [10]

Answer:

Final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

so we get:

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$

Hence final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

7 0

3 years ago