A single card is drawn from a deck. Find the probability of selecting a heart or a 9

1 answer:

6 0

Probability of heart = 13/52
probability of nine = 4/52

you add the probability because of the word "or" but must subtract the probability of drawing the 9 hearts because it's counted twice. counted once in heart probability and once again in nine probability.

probability of 9 <3 = 1/52

probability of heart or nine:
13/52 + 4/52 - 1/52 = 16/52
simplified;
= 4/13

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2x−4y=20 whats the answer

alexdok [17]

The answer is

x=10+2y

Steps:

2(x-2y)=20

x-2y=20/2 (in fraction form 20/2)

x-2y=10

X=10+2y

4 0

3 years ago

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Homework Jim Thompson! PART 2

BlackZzzverrR [31]

Problem 2

Part (a)

The 3D shape formed when rotating around the y axis forms a pencil tip

The shape formed when rotating around the x axis is a truncated cone turned on its side.

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Part (b)

Check out the two diagrams below.

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Problem 3

Answer: Choice A and Choice C

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Explanation:

Think of stacks of coins. Let's say we had 2 stacks of 10 quarters each. The quarters are identical, so they must produce identical volumes. Those sub-volumes then add up to the same volume for each stack. Now imagine one stack is perfectly aligned and the other stack is a bit crooked. Has the volume changed for the crooked stack? No, it hasn't. We're still dealing with the same amount of coins and they yield the same volume.

For more information, check out Cavalieri's Principle.

With all that in mind, this leads us to choice C. If the bases are the same, and so are the heights, then we must be dealing with the same volumes.

On the other hand, if one base is wider (while the heights are still equal) then the wider based block is going to have more volume. This leads us to choice A.

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2 years ago

What are the values of x and y x=9/4 y=3/4 x=9/4 y=15/4 x=15/4 y=5/4 x=3/4 y=15/4

laiz [17]

The complete question in the attached figure

we know that

in the triangle BDC
cos alfa=3/y----------> equation 1
sin alfa=x/y----------> equation 2

in the triangle ABD
cos alfa=4/5--------> equation 3
sin alfa=3/5---------> equation 4

then

Equal equation 1 and 3
3/y=4/5---------> y/3=5/4----------> y=15/4

Equal equation 2 and 4
x/y=3/5-------> x=3*y/5------------> 3*15/(4*5)-----> x=9/4

the answer is
x=9/4 y=15/4