What is the greatest common factor (GCF) of 36 and 54?

1-1=............... HELP!!!!!!!!!!!!!!!!!!

Verizon [17]

1-1=0 lol how do u not know this ???

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!! Multiply. (7x + 3)(4x − 5)

Anni [7]

$(7x + 3)(4x -5)$

$7x*4x+7x(-5)+3*4x+3(-5)$

$7*4xx-7*5x+3*4x-3*5$

$=28x^2-23x-15$

Hope this helps!

Thanks!

-Charlie

3 0

3 years ago

A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I

Leya [2.2K]

To solve this, we have to find the volume of the cylinder first. The formula to be used is $V = \pi r^{2} h$

Given:V= ?r= 6cmh= 10cm
Solution: $V = \pi r^{2} h$
V= (3.14)(6cm) $^{2}$ x 10cmV= (3.14)( $36cm^{2}$ ) x 10cmV= ( $113.04cm^{2}$ ) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.

5 0

3 years ago

Use the Rational Root Theorem to list all possible rational roots for the equation.

kicyunya [14]

The answer would be B and here’s the steps :)

5 0

3 years ago

Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x

egoroff_w [7]

Answer:

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

Determine the slope (m):

$y = 1 -2x$

Rearrange into slope-intercept form:

$y = -2x+1$

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of $\displaystyle\frac{1}{2}$ . Plug this into $y=mx+b$ :

$y=\displaystyle\frac{1}{2} x+b$

Determine the y-intercept (b):

$y=\displaystyle\frac{1}{2} x+b$

Plug in the given point (1,3) and solve for b:

$3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}$

Therefore, the y-intercept is $\displaystyle \frac{5}{2}$ . Plug this back into $y=\displaystyle\frac{1}{2} x+b$ :

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

I hope this helps!

8 0

2 years ago