Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
Distribute 7 to 3x and -2, and 4 to x and 5
7(3x - 2) = 21x - 14
4(x + 5) = 4x + 20
Combine like terms
21x + 4x = 25x
-14 + 20 = 6
25x + 6 is your answer
hope this helps
Answer:
66.7%
Step-by-step explanation:
The total number of complaints were:
5 + 3 + 7 = 15
The percent that came from either technicians or the Finance Department is:
(5 + 3) / 15 × 100% = 66.7%
Answer:
A - the real answer is 7
Step-by-step explanation:
g²=49 (square root 49 to get 7)
B) not sure - possibly wrote the negative sign as a mistake
