line segment connecting the vertices of a hyperbola is called the <u>transverse axis</u> and the midpoint of the line segment is the <u>center</u> of the hyperbola.
What is transverse axis and center of hyperbola ?
The transverse axis is a line segment that passes through the center of the hyperbola and has vertices as its endpoints. The foci lie on the line that contains the transverse axis. The conjugate axis is perpendicular to the transverse axis and has the co-vertices as its endpoints.
And The center of a hyperbola is the midpoint of both the transverse and conjugate axes, where they intersect. Every hyperbola also has two asymptotes that pass through its center. As a hyperbola recedes from the center, its branches approach these asymptotes.
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Answer:
12 divided by 4 is 3, this is how::
Step-by-step explanation:
------ .(-4)------- .(-4) ---------.(-4)
<---------------------------------------------------->
0 1 2 3 4 5 6 7 8 9 10 11 12
hope this made sense
The transformations are needed to transform the graph of f(x) to the graph of g(x) are:
vertical translation 1 unit up ⇒ 2nd answer
horizontal translation 5 units left ⇒ 4th answer
Step-by-step explanation:
Let us revise the translation:
- If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)
- If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)
- If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k
- If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) - k
∵ f(x) = 8x
∵ g(x) = (8x + 5) + 1
- From the notes above translation to the left h units added x by h
∵ 8x is added by 5
∴ f(x) translated 5 units to the left
- From the notes above translation up k units added f(x) by k
∵ f(x) is added by 1
∴ f(x) translated 1 unit up
The transformations are needed to transform the graph of f(x) to the graph of g(x) are:
vertical translation 1 unit up
horizontal translation 5 units left
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The dimensions of the pan are 7 inches length, 7 inches width and 2 inches height. In this case, the base is a square. The volume of the pan is equal to length times width times height equal to 7 in * 7 in * 2 in equal to 98 in3. Since there are 4 pans, the total volume is 392 in3.