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Evgen [1.6K]
3 years ago
9

In the 30-60-90 triangle below, side s has a length of _____ and side q has a length of _____.

Mathematics
2 answers:
katovenus [111]3 years ago
7 0
In a 30-60-90 triangle, the rule is:

If opposite of 30° is x,
1) Opposite of 60° is x√3
2) Opposite of 90° is 2x

When we put that into consideration, they gave us the opposite of 90° which is 8. If 8 is 2x, x or opposite of 30° is 4.

For q, we need to multiply s by √3: 4 \times \sqrt{3} = 4 \sqrt{3}

So, q is 4√3.
Slav-nsk [51]3 years ago
6 0

In a 30-60-90 triangle, the side lengths are in the ratio 1:2:sqrt(3) = short leg: hypotenuse: long leg.

We know the hypotenuse is 8. We can use this to find the other legs.

The short leg s is 8/2 = 4 because the short leg is always half of the hypotenuse.

The long leg q is 4 * sqrt(3), because the long leg is always sqrt(3) times the shorter leg.

So:

s = 4

q = 4 * sqrt(3)

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Why does a radical function with an even index only appear on one sode of the x-axis while a radical woth an odd index appears o
Vladimir79 [104]

Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.

Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.

Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.

3 0
2 years ago
Can someone please write this as a single logarithm and show work please and thank you
Mazyrski [523]

Answer:  

log_b(w^3y^4)

Step-by-step explanation:

To write the expression as a single logarithm, or condense it, use the properties of logarithms.  

1) The power property of logarithms states that log_ax^r = rlog_ax. In other words, the exponent within a logarithm can be brought out in front so it's multiplied by the logarithm. This means that the number in front of the logarithm can also be brought inside the logarithm as an exponent.  

So, in this case, we can move the 3 and the 4 inside the logarithms as exponents. Apply this property as seen below:

3log_bw+4log_by\\=log_bw^3+log_by^4

2) The product property of logarithms states that log_axy = log_ax+log_ay. In other words, the logarithm of a product is equal to the sum of the logarithms of its factors. So, in this case, write the expression as a single logarithm by taking the log (keep the same base) of the product of w^3 and y^4. Apply the property as seen below and find the final answer.  

log_bw^3+log_by^4\\=log_b(w^3y^4)

So, the answer is log_b(w^3y^4).

4 0
2 years ago
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