Speed = distance/time
distance = speed * time
let x = time covered by running
15 = run distance + walk distance
15 = 9(x) + 3(3-x)
15 = 9x + 9 - 3x
15 - 9 = 6x
6 = 6x
x = 1 hour
Therefore:
Running distance = speed * time
RD = 9km/hr * 1 hr
RD = 9km
X=1 any number is equal to 1
Answer:
See the answers below
Step-by-step explanation:
Nine
The first step is to find the common difference. That's found by using
<em><u>Common Difference</u></em>
t4 - t3
t4 = - 15
t3 = - 19
t4 - t3 = -15 - - 19
t4 - t3 = -15 + 19
t4 - t3 = 4
t1 = - 27 which is the first term.
<em><u>Explicit formula</u></em>
tn = a + (n - 1)*d
tn = - 27 + (n - 1)*4
t5 = -27 + (5 - 1)*4
t5 = -27 + 4*4
t5 = - 11
<em><u>Recursive</u></em>
tn = tn - 1 + 4
Ten
<em><u>Common difference</u></em>
t4 - t3
21 - 15
Common difference = 6
t2 = 33 - 6
t2 = 27
<em><u>Explicit formula</u></em>
tn = a + (n - 1)*d
tn = 33 + (n - 1)*6
<em><u>Recursive Formula</u></em>
tn = tn-1 + 6
There are too many answers between the 2 questions that the exact format can be followed and have it make sense. You are better off following each question and writing down the answers as you come to them.
Answer:
The answer would be 53
Step-by-step explanation:
Answer:
ln(125x
)
Step-by-step explanation: