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The complete question in the attached figure
we know that
triangle OBR is a right triangle
so
<span>applying the Pythagorean theorem
</span>OB²=OR²+RB²----> OB²=3²+4²-----> 25
OB=√25-----> OB=5 units
the answer is
OB=5 units
we know that
triangle OBR is a right triangle
so
<span>applying the Pythagorean theorem
</span>OB²=OR²+RB²----> OB²=3²+4²-----> 25
OB=√25-----> OB=5 units
the answer is
OB=5 units
A rectangle has a perimeter of length + length + width + width.
L = length of the fence.
W = width of the fence.
so the perimeter will be L+L+W+W or 2L+2W or 2(L+W).
now, we know that 120 ⩽ 2(L+W).
we also know that 168 ⩾ 2(L+W)
and we also know that whatever the length is, is twice the width, or L = 2W.
L = length of the fence.
W = width of the fence.
so the perimeter will be L+L+W+W or 2L+2W or 2(L+W).
now, we know that 120 ⩽ 2(L+W).
we also know that 168 ⩾ 2(L+W)
and we also know that whatever the length is, is twice the width, or L = 2W.