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pishuonlain [190]
3 years ago
5

Solve 15\sqrt{2}+6\sqrt{2}-5\sqrt{2}

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

6\sqrt{2}

Step-by-step explanation:

Hi!!!

I fixed your LaTeX:

15\sqrt{2}+6\sqrt{2}-5\sqrt{2}

We can add our similar elements to achieve an answer of 6\sqrt{2}.

It's a bit hard to explain! Please comment if you want more explanation.

Hope this helps!

:D

Mrrafil [7]3 years ago
4 0

Answer:

16 \sqrt{2}

Step-by-step explanation:

15\sqrt{2}+6\sqrt{2}-5\sqrt{2} \\  = (15 + 6 - 5) \sqrt{2}  \\  = (21 - 5) \sqrt{2}  \\ =  16 \sqrt{2}

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To find the area of a composite figure, separate the figure into simpler shapes whose area can be found. Then add the areas together. Be sure than none of the simpler figures have overlapping areas. Example 1: Find the area of the composite shape shown below.

Step-by-step explanation:


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What are the correct answers and why? Simple and concise explanation please!!!
dezoksy [38]

Answer:

\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}

Step-by-step explanation:

(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)

f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1

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-----------------------------------

-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4

In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.

6 0
3 years ago
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Answer:

8

Step-by-step explanation:

multiply 40 x 20 which =80

then put a point after the 8 then add a 0.

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Answer:

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Step-by-step explanation:

Given equations:

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Substituting from equation (i) for y:

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<em>dividing both </em><em>sides by 3</em><em>:</em>

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Substituting 3/2 for x in equation (i):

==> y = 2(3/2) - 6

==> y = 3 - 6

==> y = -3

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3 years ago
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