There are two factors of -36 such that one factor is 11 less than half of the other factor. Choose all the pairs of these factor s
1 answer:
Let one factor be x the other factor = 0.5x - 11 x(0.5x - 11) = -36 0.5x² - 11x + 36 = 0 x² - 22x + 72 = 0 (x - 18)(x - 4) = 0 x = 18 or x = 4 When x = 18 0.5x - 11 = 0,5(18) - 11 = -2 When x = 4 0.5 - 11 = 0.5(4) - 11 = -9 ------------------------------------------------------------------------- Answer: The pairs are (18 and -2) and (4 and -9) -------------------------------------------------------------------------
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