P= a+b+c = 76
side a = 2b = 30
side b = b = 15
side c = 2b + 1 = 31
the length is given and i got the width as 8 so you just add up all the sides and i got 40
Answer:
(C) 2
Step-by-step explanation:
Given equations 2a + 7b+2c=16 and 2a + 3b +2c= 8, you want to know the value of b.
<h3>Solution</h3>
The coefficients of 'a' and 'c' are the same in the two equations, so we can eliminate those variables by subtracting one equation from the other. We can keep the resulting coefficient of 'b' positive if we subtract the second equation from the first.
(2a +7b +2c) -(2a +3b +2c) = (16) -(8)
4b = 8 . . . . . . . simplify
b = 2 . . . . . . . divide by 4
4x^2-9
(2x+3)(2x-3)
To verify use distributed
2x(2x) +2x(-3)+3(2x)+3(-3)
4x^2-6x+6x-9
4x^2+0-9
4x^2-9
