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harkovskaia [24]
3 years ago
8

Which equation represents the value of x? x=100−y2−−−−−−−√ x=10+y2 x=10−y x=y2+100−−−−−−−√ Right triangle A B C with angle B as

the right angle. A C is equal to 10. B C is equal to y. A B is equal to x.

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

Therefore the required value of x,

x=\sqrt{(100-y^{2})}

Step-by-step explanation:

Given:

ΔBC is a Right Angle Triangle at ∠ B = 90°

As ∠ B = 90° , AC will be the Hypotenuse

AC = 10 = Hypotenuse

BC = y = Longer leg ( say )

AB = x = Shorter leg ( say )

To Find :

x = ?

Solution:

In Right Angle Triangle Δ ABC , By Pythagoras Theorem we get

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Substituting the given values we get

10^{2}= x^{2}+y^{2} \\\\x^{2}=100-y^{2} \\\\\textrm{square rooting on both the side we get}\\\\x=\sqrt{(100-y^{2})}\\\therefore x=\sqrt{(100-y^{2})}\ \textrm{ which is the required value of x}

Therefore the required value of x,

x=\sqrt{(100-y^{2})}

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let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
3 years ago
Take LCM ald then do in full process​please help me
Marina86 [1]

Answer:a) L.C.M OF 2,3,5 is 30

THEREFORE=60/30+15/30÷10/30-6/30

=60/30+15/30×30/10-6/30(DMAS)

=60/30+3/2-6/30

=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.

=105/30-6/30

=105-6/30

=99/30

=33/10

b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3

8 0
3 years ago
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