120*.75=90dollars is the sale price
Answer:
Cost of a single Mucho beef burrito: 
Cost of a double Mucho beef burrito: 
Step-by-step explanation:
<h3>
The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>
Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.
Set a system of equations:

To solve this system you can apply the Substitution Method:
1. Substitute the second equation into the first equation and solve for "y":

2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":

Answer
40.9
Step-by-step explanation:
Answer:
Answer is in the attachment.
Step-by-step explanation:
To graph x>2 consider first x=2. x=2 is a vertical line and if you want to graph x>2 you need to shade to the right of the vertical line.
To graph x+y<2, I will solve for y first.
x+y<2
Subtract x on both sides:
y<-x+2
Consider the equation y=-x+2. This is an equation with y-intercept 2 and slope -1 or -1/1. So the line you have in that picture looks good for y=-x+2. Now going back to consider y<-x+2 means we want to shade below the line because we had y<.
Now where you see both shadings will be intersection of the shadings and will actually by your answer to system of inequalities you have. In my picture it is where you have both blue and pink.
I have a graph in the picture that shows the solution.
Also both of your lines will be solid because your question in the picture shows they both have equal signs along with those inequality signs.
Just in case my one graph was confusing, I put a second attachment with just the solution to the system.