Since a rhomubs is a 4 sided quadrilateral when parallel lines intersect within we solve for the triangles that are the result of the intersecting lines m<2=10, m<3=10
If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.
For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.
Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.
In every triangle, the largest side, is opposite the largest angle.
Also, the smallest side, is opposite the smallest angle.
a.

so

,
because RQ is opposite angle P, the largest,
PR is opposite angle Q , the middle
and PQ is opposite angle R, the smallest.
Greatest side: RQ
b. The sum of the measures of the interior angles of any triangle is 180°,
so

thus, m(C) is the largest angle. This means the largest side is the side AB.
Answers:
a) RQ
b)AB
Using the formula
L=rx (x=angle)
x=L/r
x=8/3
x=2.6 radians
Answer:
460 minutes, or 7 hours and 20 minutes.
Step-by-step explanation:
Your formula is 0.14x+23=0.19x
X represents your minutes.
0.14*460+23=87.4
0.19*460=87.4