Answer:
And if we solve for a we got
And for this case the answer would be 35185 the lowest 1% for the salary
Step-by-step explanation:
Let X the random variable that represent the salary, and for this case we can assume that the distribution for X is given by:
Where
and
And we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.01 of the area on the left and 0.99 of the area on the right it's z=-2.33. On this case P(Z<-2.33)=0.01 and P(z>-2.33)=0.99
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
And for this case the answer would be 35185 the lowest 1% for the salary
Answer and Explanation:
Number of classes = 8
Highest value =2300
Lowest value = 1250
Class width= highest value – lowest value / number of classes
= 2300 – 1250/8
= 131.25 = 132
So, we can write class as 1250+132=1382
Class frequency
1250-1382 2
1382-1514 3
1514-1646 6
1646-1778 2
1778-1910 3
1910-2042 2
2042-2174 1
2174-2306 1
Answer:
x=15
Step-by-step explanation:
21-6=15
-4x+y=-5x-y=15
x+y=-y=15
x=15
Answer: D. -0.6
Step-by-step explanation:
Z score formula= x-mean/ SD
34-40/10= -3/5= -0.6
Answer:
C
Step-by-step explanation: