Answer:
should be continuous.
Step-by-step explanation:
the amount of pounds can continue to go up forever, making the graph possible infinite.
Answer:
Please take a photograph of the graph.
Answer:
this is hard
Step-by-step explanation:
A. The ratio of the person's shadow to their height is 6:2 or 3:1, so the height of the shadow is 360/3 or 120 m.
B. The model car's length divided by the ratio to the real car, which is 8.5/0.8 = 10.625 cm long.
Not much can be done without knowing what

is, but at the least we can set up the integral.
First parameterize the pieces of the contour:


where

and

. You have


and so the work is given by the integral

