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const2013 [10]
3 years ago
12

If ON= 5x - 7, LM = 4x+ 4, NM = x -7, and OL =3y-4, find the values of c and y for which LMNO MUST BE a parallelogram.

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

Answer:

x=11, y=8/3

Step-by-step explanation:

Consider quadrilateral LMNO. If this quadrilateral MUST BE a parallelogram, then

LM=NO

and

LO=MN

Thus,

\left\{\begin{array}{l}4x+4=5x-7\\ \\x-7=3y-4\end{array}\right.

Solve this system of two equations. From the first equation:

4x-5x=-7-4\\ \\-x=-11\\ \\x=11

Substitute it into the second equation:

11-7=3y-4\\ \\3y-4=4\\ \\3y=4+4\\ \\3y=8\\ \\y=\dfrac{8}{3}

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Determine whether each statement is always sometimes or never true explain your reasoning
Aneli [31]

17) Sometimes true

  • Given only that a quadrilateral is a parallelogram, we can only conclude the opposite sides are congruent - not the adjacent sides

18) Always true

  • Adjacent angles of a parallelogram are supplementary.

19) Always true.

  • Opposite sides of a parallelogram are congruent.

20) Never true

  • Diagonals of a parallelogram bisect each other, meankng that MR = RP.
8 0
1 year ago
Sam uses 2/3 cup of sugar to make cookies. How many cups will Sam use to make five batches. Write your answer in two ways. Impro
frosja888 [35]

Answer:

Improper fraction = 10/3 cups

Mixed fraction = 3 1/3 cups

Step-by-step explanation:

Given;

Sam uses 2/3 cup of sugar to make cookies

Rate = 2/3 cup per batch

To make 5 batches, he would need;

Amount = number of batches × rate per batch

Amount = 5 batches × 2/3 cups per batch

Amount of sugar he would need = 10/3 or 3 1/3 cups

4 0
3 years ago
H(x)=x−4h<br> What is the domain of h?
MAVERICK [17]

Answer:

h= x/ x+4

Step-by-step explanation:

Move all terms to the left side and set equal to zero, Then set each factor equal to zero.

3 0
3 years ago
Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math
alex41 [277]

Answer:\frac{8}{3}\times \sqrt{\frac{2}{5}}

Step-by-step explanation:

Given two upward facing parabolas  with equations

y=6x^2 & y=x^2+2

The two intersect at

6x^2=x^2+2

5x^2=2

x^2=\frac{2}{5}

x=\pm \sqrt{\frac{2}{5}}

area  enclosed by them is given by

A=\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx

A=\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx

A=4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]

A=\frac{8}{3}\times \sqrt{\frac{2}{5}}

7 0
3 years ago
Solve using the square root property.X^2=-12
Alla [95]

Answer:

x = ± 2i\sqrt{3}

Step-by-step explanation:

note that \sqrt{-1} = i

x² = - 12 ( take square root of both sides )

x = ± \sqrt{-12} = ± \sqrt{4(3)(-1)} = ± 2i\sqrt{3}

5 0
2 years ago
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