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3 years ago

How to explain if it is a domain or range of each relation of

Mathematics

1 answer:

Nostrana [21]3 years ago

8 0

This is not a function because -2 and 15 are being repeated in the domain and range.

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the area of a bathroom floor measures 2 yards by 3 yards and each custom tile that makes up the flooring is 1 1/2 square feet ho

USPshnik [31]

Its 2 x 3 = 6 so the room is 6 yards

4 0

3 years ago

Read 2 more answers

Montana Company sold merchandise with a retail price of $ 29 comma 000 for cash. Montana Company is required to collect 6 % sta

cluponka [151]

Answer:

The total cash received is $30740.

Step-by-step explanation:

Montana Company sold merchandise with a retail price of $ 29,000 for cash. Montana Company is required to collect a 6 % state sales tax.

Therefore, the total cash received from customer = Retail Price + State Sales Tax.

= $29000 + 29000 \times \frac{6}{100}$

= $30740

Hence, the total cash received is $30740. (Answer)

3 0

3 years ago

Can someone please answer my question in less than two weeks plz its ridiculos!!!

Tatiana [17]

Answer:

Step-by-step explanation:

3^-1 = .33333333

1/4 = .25

5 0

3 years ago

Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

Which equation is true for the value b = 2? 2b + 24 = 30 3b − 2 = 4 b + 4 = 8 2b − 3 = 0

faust18 [17]

The correct answer is 3b-2=4

Hope this helps.

5 0

3 years ago