Answer:
1. 9
2. 9
3. 101
Step-by-step explanation:
hope it helps:)
The radius of the cylinder before deformation is 7.5mm
<h3>Deformation of an object</h3>
From the given question, we are given that;
cold work radius of the cylinder is 10mm
Ductility = 25%
Determine the radius before deformation
Radius before deformation = (1- 0.5) + 10
Radius before deformation = 0.75 * 10
Radius before deformation = 7.5mm
Hence the radius of the cylinder before deformation is 7.5mm
Learn more on deformation here: brainly.com/question/6417346
Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
Find out more on combined area at brainly.com/question/12966430
#SPJ1
Answer:
sin²x
Step-by-step explanation:
we have
(1 − cos x)(1 + cos x)=1-cos²x
Remember that
sin²x+cos²x=1 ------> i-cos²x=sin²x
therefore
(1 − cos x)(1 + cos x)=sin²x
We have
x>=-2
x<=6
y>=-1
y<=4
using a graph tool
see the attached figure
the solution is the figure of a rectangle <span>limited by points
</span>(-2,-1) (6,-1) (-2,4) (6,4)
the answer is
a rectangle
a parallelogram (rectangles<span> are subsets belonging to the set of </span><span>parallelograms)</span>
