Answer:
-88
Step-by-step explanation:
Let N(x) be the number of students at NMS for a certain number of years.
Let S(x) be the number of students at SMS for a certain number of years.
Let x be the number of years.
N(x)=1240-25x
S(x)=800-30x
When # of students is equal, N(x)=S(x). Therefore, we are looking for the value of x (# of years) when 1240-25x=800-30x
Subtract 1240 from each side
-25x=-440-30x
Add 30x
5x=-400
x=-88 years
Check your numbers.
Answer:
$519
Step-by-step explanation:
Given the amount of profit made expressed as y=-2x^2+105x-859
At maximum profit, dy/dx = 0
dy/dx = -4x + 105
0 = -4x + 105
4x = 105
x = 105/4
x = 26.25
Substitute into the original function
y=-2x^2+105x-859
y=-2(26.25)^2+105(26.25)-859
y = - 1,378.125+2,756.25-859
y = 519.125
Hence the maximum amount of profit the company can make is $519
Answer:
1: False.
2: False.
3: True.
4: False.
5: False.
6: False.
Step-by-step explanation:
:)
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Hope this helps!
The dimensions of the rectangular cross section will be<u> 10 centimeters by 18 centimeters</u>
<u></u>
Step-by-step explanation:
As ,we know
<u>The rectangular cross section is parallel to the front face</u>
Which clearly states that
The dimensions of the rectangular cross section is congruent with the dimensions of the front face
Lets assume that dimensions of the front face are 10 centimeters by 18 centimeters
<u>Then ,The dimensions of the cross section will also be 10 centimeters by 18 centimeters</u>
<u></u>
<u>Hence we can say that the</u> dimensions of the rectangular cross section will be<u> 10 centimeters by 18 centimeters</u>
Answer:
hyp = sqRoot(6^2 + 8^2) = sqRoot(100) = 10
Step-by-step explanation: