You divide 48 by 7 and you get the remainder of 6.8 . Therefore he can ONLY put 6 books in each box.
Parallel lines have the same slope.
To compare the slopes of two different lines, you have to get
both equations into the form of
y = 'm' x + (a number) .
In that form, the 'm' is the slope of the line.
Notice that it's the number next to the 'x' .
The equation given in the question is y = 3 - 2 x .
Right away, they've done something to confuse you.
You always expect the 'x' term to be right after the 'equals' sign,
but here, they put it at the end. The slope of this line is the -2 .
Go through the choices, one at a time.
Look for another one with a slope of -2 .
Remember, rearrange the equation to read ' y = everything else ',
and then the slope is the number next to the 'x'.
Choice #4: y = 4x - 2 . The slope is 4 . That's not it.
Choice #3: y = 3 - 4x . The slope is -4 . That's not it.
Choice #2). 2x + 4y = 1
Subtract 2x from each side: 4y = 1 - 2x
Divide each side by 4 : y = 1/4 - 1/2 x .
The slope is -1/2. That's not it.
Choice #1). 4x + 2y = 5
Subtract 4x from each side: 2y = 5 - 4x
Divide each side by 2 : y = 5/2 - 2 x .
The slope is -2 .
This one is it.
This one is parallel to y = 3 - 2x ,
because they have the same slope.
Answer:
3x - 4y = -4
Step-by-step explanation:
substitute the ordered pair into each equation and ensure that it comes out to be true.
Answer:
y=-
x+
Step-by-step explanation:
First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find
m=(y2-y1)/(x2-x1)
=(2-(-4))/(-2-1)
=6/-3
=-2
in this equation the slope is 2, and to find the first equation, use y=mx+b
use the point (1, -4) to find b
-4=(2)(1)+b
-4=2+b
b=-6
the first equation of the line is y=2x-6
to find the x intercept of that line substitute 0 for y
0=2x-6
2x=6
x=3
the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2
for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b
y=mx+b
0=(-1/2)(3)+b
b=3/2
thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-x+3/2
