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solmaris [256]
3 years ago
9

Please help hard math good points

Mathematics
1 answer:
Elis [28]3 years ago
4 0

Try B...because the points meet at a intersection

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I would like some help,, no need to rush though! (20 points :])
Pepsi [2]

1. A

2. B

3. A

hope its correct

5 0
3 years ago
A pair of shoes usually sells for $67. If the shoes are 40% off, and sales tax is 8%, what is the total price of the shoes, incl
Gekata [30.6K]
If it is 40% off, it means you have to pay 60% of its price.
$67 × 60/100 = $40.20
the 8% of sales tax is added from the $40.20
$40.20 × 8/100 = $3.22
total price = $40.20 + $3.22 = $43.42
5 0
3 years ago
Which property of equality could be used to solve x - (-6) = 18?
oksian1 [2.3K]

Answer:subtraction property

Step-by-step explanation:

Two a negative and a negative makes a positive so it would be x+6=18 so u do the opposite on both sides so it would be subtraction

8 0
3 years ago
The range of a lighthouse is the maximum distance at which its light is visible. In the figure, point A is the farthest point fr
SVEN [57.7K]
4000.0093979 = 63.2456275
-15999998
= 8.7

Then you get 50
 



6 0
3 years ago
On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)
goldfiish [28.3K]

Answer:

f(x) > 0 over the interval (-\infty,-4)

Step-by-step explanation:

If  f(x)  is a continuous function,  and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from - \infty, until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from - \infty to -3, since between the  values -4 and -3 the function adopts negative values.

6 0
3 years ago
Read 2 more answers
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