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Artyom0805 [142]
3 years ago
6

What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the

measure of the acute angle is 45°? Answer: A = cm2
UUUUURRRRRRRGGGGGGEEEEEEEENNNNNNNNTTTTTT!!!!!!!!!!!
Mathematics
1 answer:
padilas [110]3 years ago
5 0

The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm.  Thus, the desired area is:

        (18 cm)(9 cm)

A = ----------------------- = 81 cm^2

                  2

This problem gives you more info than is needed to solve it.  The area of the given triangle is 81 cm^2.

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352, 345, 338, ...<br> Find the 43rd term.
Artemon [7]

Answer:

Step-by-step explanation:

first term = a = 352

Common difference = d = second term - first term

                                  = 345 - 352

                                   = (-7)

nth term = a + (n-1)*d

43rd term = 352 + (43-1)*(-7)

                 = 352 + 42 *(-7)

                  = 352 - 294

                  = 58

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Answer:

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Given the equation square root of quantity 2x plus 8 end quantity equals 6, solve for x and identify if it is an extraneous solu
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Answer:

Solution: x = 6

Step-by-step explanation:

Given equation is:

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