What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the

Question

4 years ago

6

measure of the acute angle is 45°? Answer: A = cm2
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1 answer:

padilas [110] · Answer 1 · 2021-12-23T10:15:45+03:00

The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm. Thus, the desired area is:

(18 cm)(9 cm)

A = ----------------------- = 81 cm^2

2

This problem gives you more info than is needed to solve it. The area of the given triangle is 81 cm^2.