What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the
measure of the acute angle is 45°? Answer: A = cm2
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1 answer:
The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).
Here, b = 18 cm and h = 9 cm. Thus, the desired area is:
(18 cm)(9 cm)
A = ----------------------- = 81 cm^2
2
This problem gives you more info than is needed to solve it. The area of the given triangle is 81 cm^2.
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