Multiply the bottom together to get 8 and the top is now 5x
Hope this helps, just type in the CAS
Answer: <u>1 & 5</u> are both corresponding angles
Step-by-step explanation: because they are both on the top and on the same side that's what makes them corresponding angles
<h2><u>
Love U Daddy!</u></h2>
The answer is 2 my dear friend
Answer:
39 feet
Step-by-step explanation:
In this problem, the height of the football at time t is modelled by the equation:
![h(t)=-16t^2+vt+s](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E2%2Bvt%2Bs)
where:
s = 3 ft is the initial height of the ball
v = 48 ft/s is the initial vertical velocity of the ball
is the acceleration due to gravity (downward)
Substituting these values, we can rewrite the expression as
![h(t)=-16t^2+48t+3](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E2%2B48t%2B3)
Here we want to find the maximum height reached by the ball.
This is equivalent to find the maximum of the function h(t): the maximum of a function can be found requiring that the first derivative of the function is zero, so
![h'(t)=0](https://tex.z-dn.net/?f=h%27%28t%29%3D0)
Calculating the derivative of h(t), we find:
![h'(t)=-32 t+48](https://tex.z-dn.net/?f=h%27%28t%29%3D-32%20t%2B48)
And imposing it equal to zero, we find the time t at which this occurs:
![0=-32t+48\\t=-\frac{48}{-32}=1.5 s](https://tex.z-dn.net/?f=0%3D-32t%2B48%5C%5Ct%3D-%5Cfrac%7B48%7D%7B-32%7D%3D1.5%20s)
And substituting back into h(t), we can find the maximum height of the ball:
![h(1.5)=-16\cdot (1.5)^2 + 48\cdot 1.5 +3=39 ft](https://tex.z-dn.net/?f=h%281.5%29%3D-16%5Ccdot%20%281.5%29%5E2%20%2B%2048%5Ccdot%201.5%20%2B3%3D39%20ft)