(x – h)² + (y – k)²<span> = r</span>²
Fill in the numbers
(x – 7)²<span> + (y +3)</span>²<span> = 49</span>
The linear equation that is perpendicular to the line x+3y=21 is:
y = 3*x - 6
<h3>How to find the equation of the line?</h3>
A general line in the slope-intercept form is written as:
y = m*x + b
Where m is the slope and b is the y-intercept.
Two linear equations are perpendicular if the product between the two slopes is equal to -1.
Rewriting the given line we can get:
x +3y = 21
3y = 21 - x
y = 21/3 - x/3
y = (-1/3)*x + 21/3
Then the slope is (-1/3), if our line is perpendicular to this one, then:
m*(-1/3) = -1
m = 3
our line is:
y = 3*x + b
To find the value of b, we use the fact that our line passes through (1, - 3)
-3 = 3*1 + b
-3 - 3 = b
-6 = b
The line is y = 3*x - 6
Learn more about linear equations:
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Answer:
I'm assuming you have 4 options, and if so, the answer is A.
Step-by-step explanation:
Rounding 36.6 off to 37 will make it easier to estimate the quotient when dividing by 5. For example, I can easily come up with a solution in my head when dividing 37 to 5 but it's harder for me to come up with a solution to 36.6.
We subtract the 17 from the 981 to make the two sides even so it’s easier to calculate, 981 - 17 = 964, then divide that by 2, 964/2 = 482. So your answer is 482.
Would appreciate brainliest!
Answer:
The answer is 135 degrees.
Step-by-step explanation:
As we are given the position. If we take the <u>derivative</u>, we get the velocity vector. If we take the <u>derivative</u> again, we find the acceleration vector of the particle.
At time t=0;
As i attach in the picture the angle between the velocity and acceleration vector is degrees