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marshall27 [118]
3 years ago
10

A restaurant earns $1073 on Friday and $1108 on Saturday. Write and solve an equation to find the amount xx (in dollars) the res

taurant needs to earn on Sunday to average $1000 per day over the three-day period. Write your equation so that the units on each side of the equation are dollars per day
Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0
(1073 + 1108 + x) / 3 = 1000
(2181 + x) / 3 = 1000 ....multiply both sides by 3
2181 + x = 1000 * 3
2181 + x = 3000
x = 3000 - 2181
x = 819 <== they would need to earn $ 819 on Sunday
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5 over 7 or 3 over5​
alekssr [168]

Answer:

5/7 or 3/5

Step-by-step explanation:

Sorry if I'm wrong bc I don't understand the question

7 0
3 years ago
Read 2 more answers
Please give me correct answer​
babunello [35]

Answer:

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  • 120 = 59+61 ---> They also are twin primes and their sum is 120

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6 0
3 years ago
Assignment: Translating Functions Investigation
Leto [7]

Answer:

Part A)

1) The graph in the attached figure N 1

2) The coordinate rule is (x,y) -----> (x,y+10)

3) The translation of the function up 10 units means that the initial deposit is $60 instead of $50

Part B)

1) The graph in the attached figure N2

2) The coordinate rule is (x,y) -----> (x-10,y)

3) The translation of the function right 10 units means that the initial deposit is equal to $10

Part C)

1) In each translation, the slope is the same (m=5) are parallel lines

2) The vertical translation would be up 40 units

Step-by-step explanation:

we have

f(x)=5x+50

where

f(x) --> represents Jeremy's account balance

x ---> the time in years

Part A)

The translation of the function is up 10 units.

The rule of the translation is equal to

(x,y) -----> (x,y+10)

so

The new function will be

f(x)=5x+50+10

f(x)=5x+60

The graph in the attached figure N 1

The translation of the function up 10 units means that the initial deposit is $60 instead of $50

Part B)

The translation of the function is right 10 units.

The rule of the translation is equal to

(x,y) -----> (x-10,y)

so

we have

f(x)=5x+60 ----> function Part A

The new function will be

f(x)=5(x-10)+60

f(x)=5x+10

The graph in the attached figure N 2

The translation of the function right 10 units means that the initial deposit is equal to $10

Part C)

1. Look at the translations, what characteristic of the graph stayed the same in each translation?

In each translation, the slope is the same

The slope m is equal to m=5  

Are parallel lines

2. Look at the original graph and the graph of the translation right 10 units. What vertical translation of the graph in Part B would put the graph back to its original position?

we have

f(x)=5x+10

The vertical translation would be up 40 units

The rule of the translation is equal to

(x,y) -----> (x,y+40)

so

The new function will be

f(x)=5x+10+40

f(x)=5x+50

3 0
3 years ago
Someone help me with this question please! I'm having a hard time answering it!
Ghella [55]

Step-by-step explanation:

2 * 2 for potatoes = £4

3 * 3 for carrots = £9

90p * 3 for turnips = 270p = £2.70

total price = 9+4+2.70=15.70

change = 20 - 15.70 = £4.30

4 0
3 years ago
If the term of arthematic progression decrease in magnitude then common difference must be
Tpy6a [65]

We can say that if the term of arithmetic progression decrease in magnitude then the common difference must be <u>negative</u>.

An arithmetic progression is a sequence where every term is a sum of the previous term and a common difference.

If we suppose the first term of an arithmetic progression to be a, and the common difference to be d, then the arithmetic progression goes like this:

The first term, a₁ = a,

Second term, a₂ = a₁ + d = a + d,

Third term, a₃ = a₂ + d = a + 2d,

Fourth term, a₄ = a₃ + d = a + 3d, and it goes so on up to,

The n-th term, aₙ = aₙ₋₁ + d = a + (n - 1)d.

In the question, we are asked if the term of arithmetic progression decrease in magnitude then what can we say about the common difference.

As the magnitude of the term decreases, we can show that as:

The n-th term < The first term,

or, aₙ < a₁,

or, a + (n - 1)d < a,

or, a + (n - 1)d - a < a - a {Subtracting a from both sides},

or, (n - 1)d < 0.

Since, n > 1, (n - 1) > 0, thus we get the common difference, d < 0, that is, the common difference is negative.

Thus, we can say that if the term of arithmetic progression decrease in magnitude then the common difference must be <u>negative</u>.

Learn more about arithmetic progressions at

brainly.com/question/6561461

#SPJ4

8 0
2 years ago
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